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bagirrra123 [75]
3 years ago
15

Find the distance between v = [1; 2; 3]t and w = [-2; 1;2]t

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

  |w-v| = (√11)t

Step-by-step explanation:

Using the distance formula, you find it to be (for t=1) ...

  d = √((-2-1)² +(1-2)² +(2-3)²) = √(9 +1 +1) = √11

The distance will be multiplied by t, so is ...

  |w-v| = (√11)t

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Any REAL help on #16 above??? Can someone check my answer?
babymother [125]

Answer:

The answer to your question is:th first option is correct.

Step-by-step explanation:

Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.

Equation

y - k = ±\frac{b}{a} (x - h)

Process

Find a, b

                a² = 9    

               a = 3

                b² = 5

              b = √5

              h = 0    and k = 1

Substitution

              y - 1 = ±\frac{√5}{3} (x - 0)

Equation 1

            y = \frac{\sqrt{5} }{3} x + 1

Equation 2

           y = - \frac{\sqrt{5} }{3} x + 1  

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3 years ago
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
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arsen [322]
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6 0
3 years ago
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8.
densk [106]

Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

<h3>What is the range?</h3>

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

The amount of money in tips earned by four restaurant servers waiting on 10 tables is represented by the following data sets:

Alyssa {3, 6, 2, 8, 12, 14, 5, 7, 7, 8}

Bryant {9, 2, 7, 50, 0, 5, 2, 8, 6, 8}

Camila {1, 9, 10, 3, 0, 12, 10, 9, 8, 2}

Devon {4, 2, 8, 15, 20, 7, 5, 0, 6, 2}

The IQR for Alyssa:

IQR = Q3 - Q1

IQR = 8 - 5 = 3

The IQR for Bryant:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

The IQR for Camila:

IQR = Q3 - Q1

IQR = 10 - 2 = 8

The IQR for Devon:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

Thus, Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

Learn more about the range here:

brainly.com/question/17553524

#SPJ1

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You have one hundred seventy cubes
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