P(B) = 1 - P(B') = 1 - (7/12) = 5/12
<span>P(A∩B)=<span><span>P(A∩<span>B′</span>)/</span><span>P(<span>B′</span>) </span></span>× <span><span>P(B)/</span>1
</span></span>Plugging values into the last equation we get:
<span>P(A∩B)=<span><span>1×12×5 / </span><span>6×7×12 </span></span>= <span>542</span></span>
Now we can make use of the following formula
<span>P(A|B)=<span><span>P(A∩B) / </span><span>P(B)</span></span></span><span>
by plugging in the values that we have found.
</span>
<span>5/42 is the numerator and the denominator is 5/12.
</span>
The bottom (denominator) is P(B) which equals 5/12.
<span>P(A|B)=<span><span>5×12 / </span><span>42×5 = 6/210
6/210 = 2/7
</span></span></span><span>p(a[b]) = 2/7</span>
A. Longer
The shortest wavelength on the left side is Gamma rays. The longest are radio so as you move to the right, it gets longer.
The situation would be that, in a sealed tube, there are 3 to 4 nails inside and a certain amount of calcium chloride was added. After three days, there will be no changes to be observed in the first tube since the oxygen is not enough to initiate a change and there is no presence of water. For the second test, the same situation is made but boiling water was filled in the tube. For this, no changes would still be observed since there is no moisture. For the last test, the same situation as the first but it is filled halfway with water. After 3 days, rust would be observed on the nails. In order for rust to happen, there should be water and oxygen. The oxygen in the early atmosphere of the Earth would react with iron present in the oceans thus producing iron ores.
