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g100num [7]
3 years ago
13

Find an equation of the line containing the given pair of points (4,1) and (12,7)

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

Y = 3/4 X -2

Step-by-step explanation:

Just apply the equation of a straight line (Y=mX+C), remembering that m represents the gradient of the line. This can be found by dividing the change in the y-axis by the change in the x-axis. Then substitute a set of coordinates with your obtained gradient into Y=mX+C to obtain C, i.e. the y-intercept.

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What percent of 70 is 49?
morpeh [17]

Answer:

70%

Step-by-step explanation:

49/70 = 0.7

0.7*100 = 70%

4 0
3 years ago
Solve Quantity 4x plus 15 end quantity over 5x is equal to one-half. Show all work.
almond37 [142]
((4x+15)/(5x)) = 1/2
4x+15 = (5x)/2
8x+30=5x
3x+30=0
3x=-30
x=-10
4 0
3 years ago
3. Identify each following representation as a function or nonfunctional and explain your reasoning.
Vaselesa [24]

Answer:

1.1

Step-by-step explanation:

I think it.

7 0
3 years ago
Read 2 more answers
Two dogs run around a circular track 300 m long. One dog runs at a steady rate of 15m per second, the other at a steady rate of
mihalych1998 [28]

Answer:

300 seconds

Step-by-step explanation:

The first dog run at v₁ = 15 m/sec     the second one run at  v₂ = 12 m/sec

we know that  d = v*t  then  t  =  d/v

Then the first dog will take  300/ 12  =  25 seconds to make a turn

The second will take   300 / 15   =   20 seconds to make a turn

Then the first dog in 12 turns 12*25 will be at the start point, and so will the second one at the turn 15.

To check  first dog    12 *  25 = 300

And the second dog 15 * 20 = 300

That means that time required for the two dogs to be at the start point together is

300 seconds, in that time the first dog finished the 12 turns, and the second had ended the 15.

Another procedure to solve this problem is as follows:

between  12  m/sec and  15 m/sec   the minimum common multiple  is 300 ( 300 is the smaller number that accept 12 and 15 as factors         12*15 = 300) Then when time arrives at 300 seconds the two dogs will be again in the starting point

3 0
3 years ago
Which expression is a difference of cubes 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15-a^27
cricket20 [7]
<span>A. 9w^33-y^12
B. 18p^15-q^21
C. 36a^22-b^16
D. 64c^15-a^27   -----> 64c^15 = (4c^5)^3; a^27 = (a^9)^3

Answer: D. </span>64c^15-a^27
6 0
3 years ago
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