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vlada-n [284]
3 years ago
10

Iron+COPPER SULPHATE=iron sulphate+_______?

Chemistry
1 answer:
Mrac [35]3 years ago
3 0
The answer you are missing is copper
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The ion with the smallest diameter is ________. The ion with the smallest diameter is ________. Be2 Sr2 Ca2 Ba2 Mg2
mart [117]

Answer:

Be2^+

Explanation:

Ionic diameter increases down the group. This implies that Be2^+ will have the smallest diameter.

This extremely small diameter makes Be2^+ to differ considerably from other ions of group 2 elements.

For instance, the compounds of beryllium are mostly covalent in nature.

6 0
4 years ago
How does convection heat the air?
LuckyWell [14K]
Because in a convection cycle heat rises and the cooler air sinks, more heat will be in the air than at the bottom.
8 0
3 years ago
A solution is made by mixing equal masses of methanol, CH4O, and ethanol, C2H6O. Determine the mole fraction of each component t
Serggg [28]

Answer: mole fraction of methanol = 0.590

mole fraction of ethanol = 0.410

Explanation:

We are given:

Equal masses of methanol CH_4O and ethanol C_2H_6O are mixed.

let the mass be x g.

Calculating the moles of methanol in the solution, by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{32.04g/mol}

Calculating the moles of ethanol in the solution, by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{46.07g/mol}

To calculate the mole fraction of methanol, we use the equation:

\chi_{methanol}=\frac{n_{methanol}}{n_{methaol}+n_{ethanol}}

\chi_{methanol}=\frac{\frac{xg}{32.04g/mol}}{\frac{xg}{32.04g/mol}+\frac{xg}{46.07g/mol}}=0.590

To calculate the mole fraction of ethanol, we use the equation:

\chi_{ethanol}=\frac{n_{ethanol}}{n_{methaol}+n_{ethanol}}

\chi_{ethanol}=\frac{\frac{xg}{46.07g/mol}}{\frac{xg}{32.04g/mol}+\frac{xg}{46.07g/mol}}=0.410

Thus mole fraction of methanol is 0.590 and mole fraction of ethanol 0.410 in three significant figures.

5 0
3 years ago
Which of the following changes to a pipe would increase the conductance by a factor of 12?
ivanzaharov [21]

C. Tripling the length and reducing the radius by a factor of 2 is the change to a pipe would increase the conductance by a factor of 12.

<u>Explanation:</u>

As we know that the resistance is directly proportional to the length of the pipe and it is inversely proportional to the cross sectional area of the pipe.

So it is represented as,

R∝ l /A [ area is radius square]

So k is the proportionality constant used.

R = kl/A

Conductance is the inverse of resistance, so it is given as,

C= 1/R.

R₁ = kl₁ / A₁

R₂ = kl₂/A₂

R₂/R₁ = 1/12 [∵ conductance is the inverse of resistance]

        = l₂A₁ / l₁A₂

If we chose l₁/l₂= 3 and A₂/A₁= 4 So R₂/R₁= 1/3×4 = 1/12

So tripling the length and reducing the radius by a factor of 2 would increase the conductance by a factor of 12.

6 0
3 years ago
What are the rows of the periodic table called?
Arlecino [84]

Answer:

i believe its called A. periods

4 0
2 years ago
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