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3 years ago

A molecule of antifreeze, ethylene glycol, has the formula c2h4(oh)2. how many atoms are there in one molecule of antifreeze?

Chemistry

2 answers:

Hitman42 [59]3 years ago

8 0

Answer:

the total atoms in one molecule of antifreeze = 2 + 6 + 2 = 10

Explanation:

The number of atoms in the given ethylene glycol molecule can be calculated from its molecular formula.

The molecular formula is : $C_{2}H_{4}(OH)_{2}$

The subscripts represent the multiplicity of the atoms present

Here the subscript on carbon = 2 so there are two carbon atoms

the subscript on hydrogen = 4 and two on OH, so the total hydrogen atoms = 6

The subscript on oxygen =2 so the total oxygen atoms= 2

Hence the total atoms in one molecule of antifreeze = 2 + 6 + 2 = 10

kifflom [539]3 years ago

5 0

Answer is: there are ten atoms in one molecule of antifreeze.
One molecule of ethylene glycol (C₂H₄(OH)₂) has two carbon atoms, six hydrogen atoms (4 + 2 · 1) and two oxygen atoms (2 · 1). So there are:
2 + 6 + 2 = 10 atoms.
Ethylene glycol (C₂H₄(OH)₂) is an odorless, sweet-tasting, colorless viscous liquid.

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Answer:

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Explanation:

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3 years ago

A 3.25 L solution is prepared by dissolving 285 g of BaBr2 in water. Determine the molarity.

Effectus [21]

Answer:

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Explanation:

Given data:

Volume of solution = 3.25 L

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Formula:

Molarity = number of moles of solute / L of solution

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3 years ago

Uranium has 146 neutrons; therefore its mass number is which of the following?

Vilka [71]

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3 years ago

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Question 9 (1 point)

pantera1 [17]

Answer:

8 moles of C

Explanation:

From the question given above, the following equation was obtained:

3A + 2B —> 6C

From the equation above,

3 moles of A reacted to produce 6 moles of C.

Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:

From the equation above,

3 moles of A reacted to produce 6 moles of C.

Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C

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3 years ago

What is the energy of a photon that has a wavelength of 8.6x10^3nm?

aniked [119]

Answer:

The energy of the photon is $2.311\times 10^{-20}\ J$ .

Explanation:

Given:

The wavelength of the photon is given as:

$\lambda =8.6\times 10^3\ nm\\1\ nm = 10^{-9}\ m\\\therefore \lambda = 8.6\times 10^{3}\times 10^{-9}=8.6\times 10^{-6}\ m$

The energy of a photon in terms of its wavelength is given as:

$E_p=\frac{hc}{\lambda}\\Where,\ h\rightarrow \textrm{Planck's constant}=6.626\times 10^{-34}\ Js\\c\rightarrow \textrm{velocity of light}=3\times 10^8\ m/s$

Plug in all the given values and calculate energy of the photon, $E_p$ . This gives,

$E_p=\frac{6.626\times 10^{-34} \times 3\times 10^8}{8.6\times 10^{-6}}\\E_p=\frac{19.878\times 10^{-26}}{8.6\times 10^{-6}}\\E_p=2.311\times 10^{-20}\ J$

Therefore, the energy of the photon is $2.311\times 10^{-20}\ J$ .

3 0

4 years ago