.5 as a decimal and 50% as a percent
Answer: it will take 2.5 hours for both people to meet after person B leaves.
Step-by-step explanation:
The distance between the house of person A and his cousin's house is 234 miles.
At the point where they meet, they would have travelled 234 miles.
Person A travelled at an average speed of 44 miles per hour.
Let t represent the time spent by Person A in travelling from his house to the point where they meet.
Distance = speed × time
Distance covered by person A would be
44 × t = 44t
One and half hours later, person B leaves his house to visit person A, travelling at an average speed of 62 miles per hour. This means that total time spent by person B in travelling to the point where they meet is (t - 0.5) hours. Distance covered would be
62(t - 0.5) = 62t - 31
Since the total distance covered is 234 miles, then
44t + 62t - 31 = 234
106t = 234 + 31 = 265
t = 265/106 = 2.5 hours
Step-by-step explanation:
I have used substitution method here to find the value of x and y.
77 is ur answer hope this helps u
Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
![\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%5E2%3D5%5E2%2B10%5E2%20%5C%5C%20d%5E2%5Ctext%7B%20%3D%2025%20%2B%20100%7D%20%5C%5C%20d%5E2%5Ctext%7B%20%3D%20125%7D%20%5C%5C%20d%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B125%7D%20%5C%5C%20d%5Ctext%7B%20%3D%20%7D11.2%5Ctext%7B%20mm%7D%20%5Cend%7Bgathered%7D)
