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3 years ago

What is the area of the circle below, the circle has a radius 20.5 ft.

Mathematics

1 answer:

Darya [45]3 years ago

8 0

Answer:

It is approximately 1320.25

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What is the most precise name for a quadrilateral with the following vertices:

pashok25 [27]

<h2>Therefore it is a parallelogram.</h2>

Step-by-step explanation:

Given the vertices of the quadrilateral are A(2,3) , B(7,2), C(6,-1) and D(1,0)

The length of AB is $=\sqrt{(2-7)^2+(3-2)^2}$ $=\sqrt{26}$ units

The length of BC is $=\sqrt{(7-6)^2+(2+1)^2}$ $=\sqrt{10}$ units

The length of CD is $=\sqrt{(6-1)^2+(-1-0)^2}$ $=\sqrt{26}$ units

The length of DA is $=\sqrt{(1-2)^2+(0-3)^2}$ $=\sqrt{10}$ units

The length of AC is $=\sqrt{(2-6)^2+(3+1)^2}$ $=4\sqrt{2}$ units

The length of BD is $=\sqrt{(7-1)^2+(2-0)^2}$ = $2\sqrt{10}$ units

Here length of AB = length of CD ,

length of BC= length of DA and

length of AC ≠ length of BD

In this quadrilateral, the opposite sides are equal but the diagonals are not equal

Therefore it is a parallelogram.

3 0

3 years ago

Please someone help out quick!

Black_prince [1.1K]

Answer:
$42.50

Explanation:
If you divide 34 by 4 you get 8.5. Then you just add 8.5 to 34 to get 42.50.

6 0

2 years ago

If you deposit $200 into a CD (Certificate of Deposit) with an interest rate of 1% for 3 years, how much simple interest will yo

Korvikt [17]

Answer:

Step-by-step explanation:

A=P(1+i.n)

A=200(1+0.01.x 3)

A=206

Thus 206 - 200 = $6

8 0

3 years ago

Which of the sets shown include the elements of Set Z that are both even numbers and multiples of 3? Z = {–12, –10, –9, –1, 3, 6

gregori [183]

Answer:

B. -12,6

Step-by-step explanation:

6 0

3 years ago

I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

6 0

2 years ago