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Agata [3.3K]
3 years ago
7

Liquid can flow but solid cannot give reason ​

Physics
1 answer:
Airida [17]3 years ago
6 0

<em>Answer:</em>

<em>well..</em>

<em>Explana</em><em>tion</em><em>:</em>

<em>L</em><em>iquid</em><em> can flow but solid cannot because of differences in their properties</em>

<em>property of liquid which lets it flow:</em>

  • <em>i</em><em>nter-particular</em><em> space is large</em>
  • <em>inter-particular attraction is small</em><em> </em><em>t</em><em>hese</em><em> properties tend to make the molecules of liquid free to flow</em><em> </em>

<em>property</em><em> </em><em>of</em><em> </em><em>solid</em><em> </em><em>which</em><em> </em><em>tends</em><em> </em><em>to</em><em> </em><em>obstruct</em><em> </em><em>flow</em><em>:</em>

  • <em>inter-particular</em><em> </em><em>spa</em><em>c</em><em>e</em><em> </em><em>is</em><em> </em><em>small</em><em> </em><em>and</em><em> </em><em>so</em><em> </em><em>it's </em><em>compac</em><em>t</em>
  • <em>inter-molecular</em><em> </em><em>attra</em><em>ction</em><em> </em><em>is</em><em> </em><em>strong</em><em> </em><em>hence</em><em> </em><em>no</em><em> </em><em>tenden</em><em>cy</em><em> </em><em>to</em><em> </em><em>flow</em>

<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em>

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rosijanka [135]

Answer:

a

     l_o  =52 \  m

b

      l = 37.13 \ LY

Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

            l = 37.13 \ LY

4 0
3 years ago
Pls help I need this done soon 50 points
lidiya [134]

Answer:

1,3,5

Explanation:

i think maybe dont come at me

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3 years ago
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The graph above shows the position x as a function of time for the center of mass of a system of particles of total mass 6. 0 kg
kumpel [21]

The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

m is the mass =6.0 kg

t is the time interval=2 second

From Newton's second law;

\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\

From the graph;

\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m

The change in the momentum is;

\rm \triangle P = m\tr(\frac{v-u}{t}) \\\\ \triangle P =9.3 \times \frac{12-8}{2} \\\\ \triangle P= +18.6 \  N.s

Hence, the resulting change in momentum of the system will be +18.6 Ns.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

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6 0
2 years ago
A skateboarder shoots off a ramp with a velocity of 7.1 m/s, directed at an angle of 61° above the horizontal. The end of the ra
dsp73

Answer:

Highest point reached  = 3.37 m

Explanation:

Initial velocity, = 7.1 m/s

Initial vertical velocity = 7.1 sin 61 = 6.21 m/s

Consider the vertical motion of skateboarder,

We have equation of motion, v² = u² + 2as

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          Acceleration, a = -9.81 m/s²

          Final velocity, v = 0 m/s

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                       0² = 6.21² + 2 x -9.81 x s

                       s = 1.97 m

So from ramp the position it goes up by 1.97 m

       Highest point reached = 1.97 + 1.4 = 3.37 m    

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The Nazca plate will move under the south american plate. i know its late but it will help others!
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