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dusya [7]
2 years ago
12

Assume that a gravitational anomaly in the solar system has shifted a field of asteroids into Earth’s orbit, and the field is no

w moving directly towards Earth. The asteroid field has a density of rho (asteroids/volume), and each asteroid has an average mass of m. The asteroid field stretches over a distance d in Earth’s path. Assume that the Earth moves with a velocity of v, the asteroids with u, and that be the radius of the Earth. The Earth collides with the asteroid field:
Show that the slow-down ∆v of the Earth due to the asteroid collisions is given by:
Physics
1 answer:
Mandarinka [93]2 years ago
7 0

Answer:

An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun.

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Which describes Michael Faraday’s work with electricity and magnetism?
Liono4ka [1.6K]
<span>Faraday is best known for his work regarding electricity and magnetism. His first recorded experiment was the construction of a voltaic pile with seven ha'penny coins, stacked together with seven disks of sheet zinc, and six pieces of paper moistened with salt water.</span>
5 0
3 years ago
Read 2 more answers
I have four questions.
Inga [223]

Answer:

The potential energy of the ball is 784 joules. And the kinetic energy of it is 392 while falling halfway down.

Explanation:

PE = mass (2kg) * Gravitational acceleration (9.8 m/s^2)* height (40 meters)

KE = 1/2 mass (1 kg) * velocity^2 (19.8)

7 0
3 years ago
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A pair of in-phase stereo speakers is placed side by side, 0.764 m apart. You stand directly in front of one of the speakers, 2.
Goryan [66]

Answer:

f = 2858.33 Hz

Explanation:

given,

distance between speaker (A) and the person = 2.34 m

Distance between speaker (B) and the person is AB =

            =\sqrt{(0.764)^2 + (2.34)^2}

            = 2.46 m

path difference d = BP - AP

                             = 2.46  - 2.34 m

                             = 0.12 m

now,    λ = 0.12

speed of sound =  343 m/s

    f= \dfrac{c}{\lambda}

    f= \dfrac{343}{0.12}

              f = 2858.33 Hz

the lowest frequency that will produce constructive interference is equal to

f = 2858.33 Hz

7 0
3 years ago
A 2.45 cm tall object is placed in 33.7 cm in front of a convex lens. The focal length
timofeeve [1]

Answer:

-1.65

Explanation:

First of all, we find the position of the image by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where:

f is the focal length of the lens

p is the distance of the object from the lens

q is the distance of the image from the lens

For the lens in this problem:

f = 21.0 cm (the focal length of a convex lens is positive)

p = 33.7 cm

Solving for q, we find the position of the image:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{21.0}-\frac{1}{33.7}=0.0179 cm^{-1}\\q=\frac{1}{0.0179}=55.7 cm

Then, the magnification of the image is given by:

M=-\frac{q}{p}

And substituting,

M=-\frac{55.7}{33.7}=-1.65

Which means that the image is inverted (negative sign) and enlarged (because M is larger than 1).

3 0
3 years ago
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 16.0 when the han
slava [35]

There are mistakes in the question as the unit of speed and height is not mention here.The correct question is here

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 16.0m/s when the hand is 1.80m above the ground.How long is the ball in the air before it hits the ground? (The student moves her hand out of the way.)

Answer:

t=3.37s

Explanation:

Given Data

As we have taken hand at origin and positive upward

So given data are

y_{i}=0m\\y_{f}=-1.80m\\v_{i}=16.0m/s\\a=g=9.8m/s^{2}

To find

time taken by the ball before it hits the ground

Solution

By using the common kinematic equation

y_{f}=y_{i}+v_{i}t+0.5at^{2}

Put the given values and find for t

So

-1.80=0+16.0t+(0.5*(-9.8)t^{2} )\\-1.80=16.0t-4.9t^{2}\\ 4.9t^{2}-16.0t-1.80=0

Apply quadratic formula to solve for t

t=\frac{-(-16.0)+\sqrt{(-16)^{2}+4(4.9)(-1.80)} }{2(4.9)}\\ t=3.37s

4 0
4 years ago
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