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dusya [7]
2 years ago
12

Assume that a gravitational anomaly in the solar system has shifted a field of asteroids into Earth’s orbit, and the field is no

w moving directly towards Earth. The asteroid field has a density of rho (asteroids/volume), and each asteroid has an average mass of m. The asteroid field stretches over a distance d in Earth’s path. Assume that the Earth moves with a velocity of v, the asteroids with u, and that be the radius of the Earth. The Earth collides with the asteroid field:
Show that the slow-down ∆v of the Earth due to the asteroid collisions is given by:
Physics
1 answer:
Mandarinka [93]2 years ago
7 0

Answer:

An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun.

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What distance does a police car travel if it is going 3.0 m/s for 20 seconds
Vladimir79 [104]

Answer:

60 meters

Explanation:

If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply

3meters/second*20seconds

cross out the seconds and you have

3 meters*20

60 meters

6 0
2 years ago
Look at the graph pic and answer the question correctly!
SCORPION-xisa [38]

Answer:

B)

Explanation:

That the time period of which they stop.

4 0
3 years ago
Read 2 more answers
Two electrons are separated by a distance of 3.00 x 10^-6 meter. What are the magnitude and direction of the electrostatic force
Brilliant_brown [7]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where 
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
r=3.00 \cdot 10^{-6} m is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 
q_1=q_2=q=-1.6 \cdot 10^{-19}C

By substituting these values, we find the intensity of the force between the two electrons:
F=(8.99 \cdot 10^9 N m^2 C^{-2})  \frac{(-1.6 \cdot 10^{-19}C)(-1.6 \cdot 10^{-19}C)}{(3.00 \cdot 10^{-6} m)^2}=2.6 \cdot 10^{-17}N

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
5 0
3 years ago
What are pollutants of greatest concern and who is at risk?
atroni [7]
Oil leakage in aquatic areas. (fish)
Burning fuel. (Air/global warming)
Toxic waste burried in dirt (living Creatures)
Lights/Electricity (destroyes Birds migration)
Noise (migration on dolphines and other sea mammals)
6 0
3 years ago
8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (
love history [14]

(1) acceleration, a = 4 m/s^{2}  (2) acceleration of 10 N, a_{1} = 1 m/s^{2} and acceleration of 30 N, a_{2} = 3 m/s^{2}

Explanation:

  • Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
  • Let a_{1} be the acceleration for force 10 N, to find acceleration rearrange the equation to a = \frac{F}{m}. When we substitute 10 N force and 10 kg mass of the box in the equation. We will get a_{1} = 1 m/s^{2}
  • Let a_{2}  be the acceleration for force 30 N, to find acceleration rearrange the equation to F = \frac{F}{m}. When we substitute 30 N force and 10 kg mass of the box in the equation. We will get a_{2} = 3 m/s^{2}
  • To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/s^{2}
3 0
3 years ago
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