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xxTIMURxx [149]
3 years ago
7

two charges + 2.6 uc and -5.4uc experience an attractive force of 6.5mN. What is the separation between the charges?

Physics
1 answer:
djyliett [7]3 years ago
7 0

Answer:

...

Explanation:

....

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if a car that is 100 feet in front of you on route 70 west slams on the brakes while you are traveling 65 miles per hour (95 fee
fenix001 [56]

Answer:

t = 1.05 s

Explanation:

Given,

The distance between your vehicle and car, 100 ft

The constant speed of your vehicle, u = 95 ft/s

Since, the velocity is constant, a =0

If the car stopped suddenly, time left for you to hit the brake, t = ?

Using the second equation of motion,

                           S = ut + ½ at²

Substituting the given values in the equation

                           100 = 95 x t

                             t = 100/95

                               = 1.05 s

Hence, the time left for you to hit the brakes and stop before rear ending them, t = 1.05 s

5 0
2 years ago
A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric
Liula [17]

The electric field produced by a single-point charge is given by

E(r)=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge


To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.


1) The first charge is q=-3.00 nC=-3.00 \cdot 10^{-9} C, and it is located at x=0, so its distance from the point x=0.200 m is

r=0.200 m-0=0.2 m

Therefore, the electric field is

E_1=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(3.0 \cdot 10^{-9} C)}{(0.2 m)^2}=675 N/C

And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.


2) The second charge is q=-5.50 nC=-5.5 \cdot 10^{-9}C and it is located at x=0.800 m, so its distance from the point is

r=0.800 m-0.200 m=0.6 m

Therefore, the electric field is

E_2 = (8.99 \cdot 10^9 Nm^2C^{-2})\frac{(5.5 \cdot 10^{-9} C)}{(0.6 m)^2}=137.5 N

And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.


3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C

and the sign tells us that the field is directed toward negative x-direction.

7 0
3 years ago
PLS HELP THIS IS DUE TODAY!!!!!!!!!
Juli2301 [7.4K]

The speed at which the objects were attracted to each other determined by the gravitational pull.

<h3>What is gravity?</h3>

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity or gravitational pull.

The gravitational force, Fg is the attractive force exerted by the Earth on the object that is equal to the mass of the object times the gravitational acceleration.

When the two objects are attracted, the speed with which they are moving toward each other depends on the strength of the pull force. This pull force is the gravitational pull.

Thus, the speed at which the objects were attracted to each other determined by the gravitational pull.

Learn more about gravity.

brainly.com/question/4014727

#SPJ1

3 0
2 years ago
Alice and Marge are studying the properties of matter. The girls placed some an iron nail in a beaker containing water. Iron is
tatuchka [14]

Answer:

When substances made of iron are exposed to oxygen and moisture (water), rusting takes place. Rusting removes a layer of material from the surface and makes the substance weak. Rusting is a chemical change.

7 0
3 years ago
If a frictional force of 4 N is acting against a push of 53 N and the box that is being pushed is 4 kg, what is its acceleration
kifflom [539]

Answer:

gggggggggggg

Explanation:

3 0
2 years ago
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