The horizontal force : f = k*N
k- coefficient of friction
k = f /N
N = m * g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057
The maximum torque that can act on the loop is 7.875 N-m.
Torque:
Torque is a twisting or turning force that tends to cause rotation around an axis, which might be a center of mass or a fixed point. Torque can also be thought of as the ability of something that is rotating, such as a gear or a shaft, to overcome turning resistance.
The formula of torque:
Torque(T) = I B A
B = magnetic field of intensity
I = current =
A = area of the wire
l = length of the wire
l = 2πr
r = l/2π
A = πr²
= π(l/2π)²
= l²/4π
T = l²/4π IB
=( 1/4π) BIl²
= (1/4π) 0.30 × 150 ×× 2.20
= 7.875 N-m
Therefore the torque is 7.875 N-m.
To know more about the Torque refer to the link given below:
brainly.com/question/1691855
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Answer:
Explanation:
According to question,
Charge 1 and charge 2 are 
The distance between charges is 2 m
We need to find the force with which two positive charges repel. It is called electrostatic force of repulsion. It can be given by :
So, the electric force of repulsion is 
.
Answer:
If I understand correctly. Line B is parallel to the circle. Also, the angle is less than 90.
- The size of the circle determines.
- The diameter should not be fixed either.
