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elena55 [62]
2 years ago
13

Calculate the frequency of the wave shown below.

Physics
1 answer:
jenyasd209 [6]2 years ago
5 0

\color{skyblue}{ \underline{  \frak { \: option \: ( \: c \: )  =  2 \: hertz   ✓}}}

\:  \:

Given :

  • Wavelength ( λ ) = 2 m

\:  \:

  • Speed = 4 m/s

\:  \:

We, have to find frequency :

\:

  • \large \tt \: Frequency =  \frac{Speed}{Wavelength ( \: λ \: )}

\:  \:

  • \large \tt \: Frequency =  \frac{4}{2}

\:  \:

  • \large \tt \: Frequency = \cancel  \frac{4}{2}

\:  \:

  • \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}

\:  \:

Hope Helps!

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Answer:

GE = ME - \frac{1}{2} m\,v^2,  which agrees with option C in your list.

Explanation:

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Given that the KE is: \frac{1}{2} m\,v^2,

solving for GE in the formula above gives:

GE = ME - KE = ME - \frac{1}{2} m\,v^2,  which agrees with option C

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4 0
2 years ago
Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 60 and 3
Scilla [17]

Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

Shear stress = 6.2 MPa

Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

\tau=\sigma\cos\alpha\cos\beta

Put the value into the formula

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Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

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Now, We need to calculate the applied stress necessary for the crystal to yield

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Put the value into the formula

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3 years ago
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