2 years ago

Calculate the frequency of the wave shown below.

Physics

1 answer:

jenyasd209 [6]2 years ago

5 0

$\color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}$

$\: \:$

Given :

Wavelength ( λ ) = 2 m

$\: \:$

Speed = 4 m/s

$\: \:$

We, have to find frequency :

$\:$

$\large \tt \: Frequency = \frac{Speed}{Wavelength ( \: λ \: )}$

$\: \:$

$\large \tt \: Frequency = \frac{4}{2}$

$\: \:$

$\large \tt \: Frequency = \cancel \frac{4}{2}$

$\: \:$

$\pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}$

$\: \:$

Hope Helps!

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A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s by a 5620 N braking force actin

Dennis_Churaev [7]

Answer:

the distance traveled by the car is 42.98 m.

Explanation:

Given;

mass of the car, m = 2500 kg

initial velocity of the car, u = 20 m/s

the braking force applied to the car, f = 5620 N

time of motion of the car, t = 2.5 s

The decelaration of the car is calculated as follows;

-F = ma

a = -F/m

a = -5620 / 2500

a = -2.248 m/s²

The distance traveled by the car is calculated as follows;

s = ut + ¹/₂at²

s = (20 x 2.5) + 0.5(-2.248)(2.5²)

s = 50 - 7.025

s = 42.98 m

Therefore, the distance traveled by the car is 42.98 m.

5 0

2 years ago

When air resistance equals the weight of an object, the object has reached

MissTica

Answer:

When air resistance equals the weight of an object, the object has reached free fall.

Explanation:

When an object has only force acting on it as gravity then, it experiences free fall.
During free fall all the forces except gravity is balanced by one another.
In the question, object's weight is balanced by air resistance so it is in the state of free fall.
At the null point of free fall, object experiences weightlessness i.e. it feels like object is not attracted by any force.