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elena55 [62]
2 years ago
13

Calculate the frequency of the wave shown below.

Physics
1 answer:
jenyasd209 [6]2 years ago
5 0

\color{skyblue}{ \underline{  \frak { \: option \: ( \: c \: )  =  2 \: hertz   ✓}}}

\:  \:

Given :

  • Wavelength ( λ ) = 2 m

\:  \:

  • Speed = 4 m/s

\:  \:

We, have to find frequency :

\:

  • \large \tt \: Frequency =  \frac{Speed}{Wavelength ( \: λ \: )}

\:  \:

  • \large \tt \: Frequency =  \frac{4}{2}

\:  \:

  • \large \tt \: Frequency = \cancel  \frac{4}{2}

\:  \:

  • \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}

\:  \:

Hope Helps!

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A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 20 m/s by a 5620 N braking force actin
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Answer:

the distance traveled by the car is 42.98 m.

Explanation:

Given;

mass of the car, m = 2500 kg

initial velocity of the car, u = 20 m/s

the braking force applied to the car, f = 5620 N

time of motion of the car, t = 2.5 s

The decelaration of the car is calculated as follows;

-F = ma

a = -F/m

a = -5620 / 2500

a = -2.248 m/s²

The distance traveled by the car is calculated as follows;

s = ut + ¹/₂at²

s = (20 x 2.5) + 0.5(-2.248)(2.5²)

s = 50 - 7.025

s = 42.98 m

Therefore, the distance traveled by the car is 42.98 m.

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Answer:

When air resistance equals the weight of an object, the object has reached free fall.

Explanation:

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Explanation:

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