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worty [1.4K]
3 years ago
10

Which statements below are true?

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

A. Distance is always greater than or equal to the magnitude of the

displacement

Step-by-step explanation:

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Please help with question 14!! BRAINLIEST to correct answer!
dexar [7]

Answer: true

Step-by-step explanation:

Hope this helps

8 0
3 years ago
Order these numbers from least to greatest. 8.23 , 7.37 , 7.307 , 7.7
Ksenya-84 [330]
7.307, 7.37, 7.7 , 8.23
6 0
3 years ago
Read 2 more answers
Find the constant rate of change for each linear function and interpret its meaning
Marina CMI [18]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

and to get it, we simply need two points off of the straight line, hmm let's use the ones in the picture below.

(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

3 0
2 years ago
3. (02.01)
sashaice [31]

Answer:

A. 1

Step-by-step explanation:

3(x+1)=-2(x-1)+6

3x+3=2x-2+6

x+3=4

x=1

7 0
3 years ago
i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
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