A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
Answer:
The sigma notation would look like this:
∞
Σ 48(1/4)^i-1
i = 1
Step-by-step explanation:
I can't seem to find a good way to make it more connected so I'll just have to tell you. The ∞ is above the ∑, while the i = 1 is under it. That is all one thing. The rest is followed as normal, and it is all next to the ∑
rearrange into the form y = mx + b
subtract 6x from both sides of the equation
7y = - 6x + 14
divide all terms by 7
y = - 
x + 2 → in slope- intercept form
It's hard to have √2 points in a basketball game (or almost any game). The number of points scored is a discrete random variable, usually restricted to non-negative integers.
