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NemiM [27]
3 years ago
9

What number should be added to both sides of the equation to complete the square?

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

16

Step-by-step explanation:

Given

x² + 8x = 4

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(4)x + 16 = 4 + 16, thus

(x + 4)² = 20 ← equivalent equation

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The angle measurements in the diagram are represented by the following expressions.
Rina8888 [55]

Answer:

since those 2 lines are parrelel that means the angles are the same so

8x+6=4x+38

minus 6

8x=4x+32

minus 4x

4x=32

divide by 4

x=8

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Formula for the volume of a cylinder is pi radius squared times height so this one would be pi times 25 times 4 which approximately equals 314
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Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not
IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=4,\ hypotenuse=10

Substitute:

4^2+leg^2=10^2

16+leg^2=100             <em>subtract 16 from both sides</em>

leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}

sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}

Substitute:

hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}

\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}

5 0
3 years ago
What is (2x2 + 4x − 3)(x2 + 2) distributived ?
Effectus [21]

Answer:

2x⁴ + 4x³ + x² + 8x - 6

Step-by-step explanation:

(2x² + 4x - 3)(x² + 2)

2(x² + 2) · x² + 4x(x² + 2) - 3(x² + 2)

2x⁴ + 4x² + 4x(x² + 2) - 3(x² + 2)

2x⁴ + 4x² + 4x³ + 8x - 3x² - 6

2x⁴ + x² + 4x³ + 8x - 6

2x⁴ + 4x³ + x² + 8x - 6

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Answer:

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