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Stolb23 [73]
3 years ago
11

If 1.45 moles of Sodium Bromide are added to a 7.5 M solution, what is the volume of the solution made?

Chemistry
1 answer:
timurjin [86]3 years ago
3 0

Answer:

0.193 L

Explanation:

Another way of writing the question would be: What volume of a 7.5 M Sodium Bromide solution would contain 1.45 moles.

To answer that we can use the <em>definition of molarity</em>:

  • Molarity = moles / liters

We <u>input the given data</u>:

  • 7.5 M = 1.45 moles / liters

And <u>calculate how many liters are required</u>:

  • 1.45 mol / 7.5 M = 0.193 L
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(taken from a user on Yahoo from Correct Answers)
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4 years ago
Think of a resource and predict What happens to the resource when competition for it increases
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3 years ago
What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

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pH=7.00

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Balanced chemical equation:

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