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Blizzard [7]
3 years ago
5

When Wolverine’s 10-pound adamantium claws are dissolved in 100 mL of 10 M nitric acid, 10.7 grams of adamantium nitrate are rec

overed. If we expected 15.0 grams of adamantium nitrate to be recovered in a complete reaction, what was the percent yield?
Chemistry
1 answer:
Mazyrski [523]3 years ago
7 0

The percent yield is 71.3 %.

Explanation:

Percent yield is the measure to analyze the success percentage of any experiment .The percent yield of any experiment can be obtained by the ratio of actual or experimental value to expected or theoretical value multiplied with 100.

Percent Yield = \frac{Experimental Outcome}{Theoretical Outcome} *100

So, in the present problem, we have obtained 10.7 g of adamantium nitrate from Wolverine's 10 pound claws. So the actual value or the experimental value is the amount of adamantium nitrate obtained from Wolverine's claws.

Thus, the experimental outcome is 10.7 g. While we had expected to recover 15 g of adamantium nitrate. So the theoretical outcome is 15 g.

Percent yield = \frac{10.7}{15} * 100 = 71.3 %

Thus, the percent yield is 71.3 %.

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If 10.00 mL of the solution prepared in question 4 is used to make another 125.00 mL solution of NaCl, what is the new concentra
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<h3>Dilution</h3>

From the question, we are to determine the concentration of the new solution prepared from question 4.

NOTE: Question is provided below

From question 4, the concentration of the sodium chloride solution is 0.200M

Now, to determine the new concentration,

Using the dilution law

C₁V₁ = C₂V₂

Where

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V₁ is the initial volume

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and V₂ is the final volume

Then,

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Question 4:

Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution

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