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3 years ago

Find the surface area of the figure. Round the the nearest hundredth.

Mathematics

1 answer:

Georgia [21]3 years ago

6 0

Answer:

Step-by-step explanation:

surface area of cylinder=2πrh

SA=1/2×2×π×3×25+2 ×(1/2×π×3²)=75π+9π=84π≈84×3.14≈263.76 cm²

if lowerside is also counted then area of lower side=25×6=150

total surface area=263.76+150=413.76 cm²

if we take π=22/7

84 π=84×22/7=12×22=264 cm²

if base is also counted then area=264+150=414 cm²

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a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

$d \times 0.10 + q \times 0.25 = 19.85$

0.1d + 0.25q = 19.85 -------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

Thus number of dimes were 81 and number of quarters were 47

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Pepsi [2]

Answer:

See below.

Step-by-step explanation:

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alukav5142 [94]

$\sqrt{16}\times\sqrt{12}$

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