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Alenkinab [10]
3 years ago
5

Find the surface area of the figure. Round the the nearest hundredth.

Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

Step-by-step explanation:

surface area of cylinder=2πrh

SA=1/2×2×π×3×25+2 ×(1/2×π×3²)=75π+9π=84π≈84×3.14≈263.76 cm²

if lowerside is also counted  then area of lower side=25×6=150

total surface area=263.76+150=413.76 cm²

if we take π=22/7

84 π=84×22/7=12×22=264 cm²

if base is also counted then area=264+150=414 cm²

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(99 POINTS) Using similarity solve for x. Show all work
Anna11 [10]
Hey there! :D

The biggest thing to remember here is the similar triangles and their side lengths. 

Okay, so we can separate these triangles into 3 similar triangles. Which, we only need to do that to two for a proportion, but if you were to have more variables, you could separate the triangles even more if you needed to. 

We want to find two triangles that have "x" has a value of their side, so we can solve a proportion. 

The bigger triangle, (the whole two triangles combine) and the smaller triangle on the left can be used to make a proportion.

On the smaller triangle:

We have 9 cm on the shorter side and x as the hypotenuse. 

On the larger triangle: 

We have x as the shorter side, and then 25 as the hypotenuse. (9+16)

Note: You have to flip the larger triangle upside down to make it a similar structure to the other two triangles. It is similar, you just have to flip it. 

So, now we can make a proportion. 

\frac{x}{9} =  \frac{25}{x}

Now, cross multiply. 

9*25= 225

x*x= x^{2}

So, find the square root. 

√225= 15

x= 15. 

I hope this helps!
~kaikers
7 0
3 years ago
Read 2 more answers
There are 500 students in a high school senior class. Of these 500 students, 300 regularly wear a necklace to
andre [41]

Answer:

<u>1. P(N) =  3/5</u>

<u>2. P(R) =  2/5</u>

<u>3. P(N and R) = 1/4</u>

<u>4. P(N or R) = 3/4</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the problem correctly:

Number of students in a high school senior class = 500

Number of students that regularly wear a necklace = 300

Number of students that regularly wear a ring = 200

Number of students that wear a necklace and a ring = 125

2. What is P(N), the probability that a senior wears a necklace?

Let's recall the formula of probability:

Probability = Number of favorable outcomes/Total of possible outcomes

Substituting with the real given values:

P(N) = 300/500 = 3/5 (Dividing by 100 numerator and denominator)

<u>P(N) =  3/5</u>

3. What is P(R), the probability that a senior wears a ring?

Substituting with the real given values:

P(R) = 200/500 = 2/5 (Dividing by 100 numerator and denominator)

<u>P(R) =  2/5</u>

4. What is P(N and R), the probability that a senior wears a necklace and a ring?

Substituting with the real given values:

P(N and R) = 125/500 = 1/4 (Dividing by 125 numerator and denominator)

<u>P(N and R) = 1/4</u>

5. What is P(N or R), the probability that a senior wears a necklace or a ring?

P(N or R) = P(N) + P(R) - P(N and R)

Substituting with the real given values:

P(N or R) = 3/5 + 2/5 - 1/4

P(N or R) = 5/5 - 1/4

P(N or R) = 1 - 1/4

<u>P(N or R) = 3/4</u>

5 0
3 years ago
In a parallel circuit, the supply voltage is 120 V, 60 Hz. The resistance is 30 Ω and the inductive reactance is 40 Ω. What is t
kvasek [131]

Given : supply voltage = 120V;60 Hz

Inductive Reactance (X_{L}) = 40 Ω

The inductive reactance is given by the formula, X_{L}=Lw, where L is inductance and w is given by formula, w = 2\pi(frequency)

Apply this, we can say that, L = \frac{X_{L}}{2\pi (frequency)}  = \frac{40}{2(3.14)(60)} = 0.106157 H = 106.157 mH

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3 years ago
Please answer the question in the picture!
Juli2301 [7.4K]
Eight units I'm pretty sure
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3 years ago
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Which fact is related to 12 : 3 = 4
goblinko [34]

Answer:

3x4 = 12 is the most related fact to 12:3 = 4

Step-by-step explanation:

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3 years ago
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