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2 years ago

9

How to subtract fractions

2 answers:

elena-s [515]2 years ago

5 0

Yes, give me a points

Alex787 [66]2 years ago

4 0

Make the denominators the same then subtract

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2(h-8)-h=h-16 what is the solution

BartSMP [9]

STEP-BY-STEP SOLUTION:

To solve this equation, first make ( h ) the subject and then simplify as much as possible as displayed below:

2 ( h - 8 ) - h = h - 16

2h - 16 - h = h - 16

2h - h - h = - 16 + 15

h = 0

Please mark as brainliest if you found this helpful! :)
Thank you <3

4 0

3 years ago

What value of x makes the statement true?

Sergeu [11.5K]

Answer:

5x-1=10x+3x

5x-3x=10+1

2x=11

x=11/2

8 0

2 years ago

Read 2 more answers

Find the largest prime divisor of 76^2 − 1.

saveliy_v [14]

Answer:

11

Step-by-step explanation:

This is a difference of squares and therefore can be written as (76-1)(76+1)=(75)(77).

So lets look at the factors....

75=3(25)=3(5)(5)

77=7(11)

The biggest prime factor is therefore 11.

Identities used:

Difference of squares a^2-b^2=(a-b)(a+b)

3 0

3 years ago

2/x2-9 - 3x/ x2-5x+6 please show work

Luda [366]

Answer: -3x^3 - 7x^2 - x + 39

Step-by-step explanation:

2/(x^2 -9) - 3x/(x^2-5x+6)

get those denominators factored out

2/(x-3)(x+3) - 3x/(x-3)(x-2)

Multiply both by both denominators

2(x-3)(x-2) - 3x(x-3)(x+3)

Multiply it out

(2x^2 - 10x + 12) - (3x^3 + 9x^2 -9x - 27)

Simplify and it becomes

-3x^3 -7x^2 -x + 39

5 0

2 years ago

Write the equation of a possible rational

kondor19780726 [428]

Answer:

The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)

Step-by-step explanation:

A rational equation is a equation where

$\frac{p(x)}{q(x)}$

where both are polynomials and q(x) can't equal zero.

1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

$(x - 2)$

in our denomiator.

So right now we have

$\frac{p(x)}{(x - 2)}$

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.

We can model -2.5 as

$(2x + 5)$

So we have as of right now.

$\frac{(2x + 5)}{(x - 2)(2x + 5)}$

Now let see if this passes throught point (6,-3).

$\frac{(2x + 5)}{(x - 2)(2x + 5)} = y$

$\frac{(17)}{68} = \frac{1}{4}$

So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.

If we have a variable r, in the numerator that will make this applicable, we would get

$\frac{(2x + 5)r}{(2x + 5)(x - 2)} = - 3$

Plug in 6 for the x values.

$\frac{17r}{4(17)} = - 3$

$\frac{r}{4} = - 3$

$r = - 12$

So our rational equation will be

$\frac{ - 12(2x + 5)}{(2x + 5)(x - 2)}$

or

$\frac{ - 24x - 60}{2 {x}^{2} + x - 10}$

We can prove this by graphing

5 0

2 years ago