Answer:
11.2
Step-by-step explanation:
well i'm guessing that you didn't finish you parenthesis and if you did they would be around the 0 and 3 so 3 plus 0 is 3 and 3 plus 8.2 is 11.2 so I believe your answer is 11.2. Sorry if it is wrong the question didn't really make sense.
Please mark brainliest
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z = ~ N(0,1)
where, = average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( 12)
P( 12) = P( ) = P(Z 1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Answer:
8. -385°, 335°
9. -30°, 330°
Step-by-step explanation:
8. θ = -25°
-25-360 = -385°
-25+360 = 335°
9. θ = -390°
-390+360 = -30°
-30+360 = 330°
Answer:
1200 ml per hour
Step-by-step explanation:
To compute what rate is 300 ml over 15 mins as a rate of ml per hour, we do a rule of 3, using a variable x as that amount of ml we don't know yet. We should have everything in the same units, so instead of writing 1 hour we write 60 minutes:
Now we solve for x:
And so, now that we know the value of x, the rate we wanted to find is
Which is just 1200 ml per hour.
A ∩ B = {3, 6, 9, 12} ∩ {2, 4, 6, 8, 10, 12}
= {6, 12}