Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
Answer:
<em>p ≥ 5</em>
<em>Scott will buy at least 5 kilograms of candy.</em>
Step-by-step explanation:
<u>Inequalities</u>
The candy Scott buys cost $7 per kilogram.
Let's set p=number of kilograms of candy Scott will buy.
The money spent to buy p kilograms of candy is 7p dollars.
The condition states he will spend at least $35 on candies, thus the following inequality is formed:
7p ≥ 35
Dividing by 7:
p ≥ 35/7
Operating:
p ≥ 5
Scott will buy at least 5 kilograms of candy.
Answer:
10
Step-by-step explanation:
150 divided by 15 is 10 and boom you have your answer
Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.