X²+3x-21=0
1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2
2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21
Answer: the product of the 2 solutions of this equation is -21
Answer:
15
Step-by-step explanation:
The difference between consecutive integers is 1.
The difference between consecutive odd integers is 2.
Let the smallest odd integer be x.
Then the next greater one is x + 2. The greatest one is x + 4.
"3 times the first" is 3x
"twice the third" is 2(x + 4)
"3 times the first of three consecutive odd integers is 3 more than twice the third"
3x = 2(x + 4) + 3
3x = 2x + 8 + 3
x = 11
The smallest integer is 11.
x + 4 = 11 + 4 = 15
The greatest one is 15.
Just remove the parenthesis since you are adding them and combine like terms
x+5+2x+3
3x+8
It’s 55 because lil baby is Galatea
Answer:
<CPB
Step-by-step explanation:
Because <APE= right angle
<APC= Obtuse angle
<CPE= Obtuse Angle.
Also, <CPB because its the only angle below 90 degrees and an acute angle must be below 90 degrees.
