Answer:
Step-by-step explanation:
Given that:
Number of Large Marbles = 14
Number of Small Marbles = 11
Number of Green large marbles = 8
Number of White small marbles = 5
We can now find the number of white large marbles and green small marbles from the information stated above.
No of white large marble = total large marble minus green large marble
= 14-8
= 6
No of green small marbles = Total small marbles minus white small marble.
= 11-5
= 6
Let the following be represented
( X,Y, Z,Q ) as follows:
Let Y be the event of drawing small marble
Let X be the event of drawing large marble
Let Q be the event of drawing white marble
Let Z be the event of drawing green marble.
Since, only one marble is drawn at a time we calculate,
P( X ) = 14/25
P( Y) = 11/25
P(Z) = 14/25
P( Q) = 11/25
P(Y∪Q)=P(Y)+P(Z)−P(Y∩Z)...(1)
We need to find the value of
P(Y∩Z)
In 11 small marbles there are 6 green marbles so the value of P(Y∩Z) is given by P(Y∩Z)=6/11
Therefore, substitute the values in equation 1.
P(Y∪Z)=P(Y)+P(Z)−P(Y∩Z)=11/25+14/25-
6/11
=0.44+0.56−0.5455
= 1-0.5455
= 909/2000
= 0.4545
Then, one can conclude that the probability of drawing a small or green marble is 0.4545
