Answer:
hmax=81ft
Explanation:
Maximum height of the object is the highest vertical position along its trajectory.
The vertical velocity is equal to 0 (Vy = 0)
we isolate th (needed to reach the maximum height hmax)
The formula describing vertical distance is:
So, given y = hmax and t = th, we can join those two equations together:
if we launch a projectile from some initial height h all you need to do is add this initial elevation
Answer:
when the mass of the bottle is 0.125 kg, the average height of the beanbag is 0.35 m.
when the mass of the bottle is 0.250 kg, the average maximum height of the beanbag is 0.91m.
when the mass of the bottle is 0.375 kg, the average maximum height of the beanbag is 1.26m.
when the mass of the bottle is 0.500 kg, the average maximum height of the beanbag is 1.57m.
Explanation:
Work done is the distance a force acts over.
So, the work done here is 9.0N * 3.0m = 27 J
If a person drives 4 miles east, then 3 miles west, here are the facts:
They are 1 mile away from where they started.
They have driven a total of 7 miles.
Answer:
Wavelenght is 4.53x10^-7m
Explanation:
Detailed explanation and calculation is shown in the image below
