Answer:
a) t = 0.25 s, b) x = 0.075 m
Explanation:
a) For this exercise we will use kinematic relationships in one dimension
v = v₀ + a t
in the problem they indicate the initial velocity v₀ = 0.15 m / s, the final velocity v = 0.45 m / s and the acceleration of the squid a = 1.2 m / s²
t =
we calculate
t =
t = 0.25 s
b) We can also find the distance traveled during this acceleration
v² = v₀² + 2a x
x =
let's calculate
x =
x = 0.075 m
Answer:
A) The new amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please find the attached files for the solution
Answer:
<em>P=mgh</em>
<em>P=mghm=55</em>
<em>P=mghm=55g=9.8 or ~10</em>
<em>P=mghm=55g=9.8 or ~10h=27</em>
Explanation:
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