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lana66690 [7]
3 years ago
5

How does the density of water change when: (a) it is heated from 0o

Physics
1 answer:
Radda [10]3 years ago
3 0

Answer:

[b] it id heated from 4o

Explanation:

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A shopping mall has a length of 200 m and a width of 75 m. What is the area of the mall?
sweet [91]
To find the area, we just need to multiply the length by the width. 200 x 75 = 15,000. The mall has an area of 15,000 sq. feet.
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3 years ago
How much time would it take for the sound of thunder to travel 1,500 meters if sound travels at a speed of 330 m/sec?
Fittoniya [83]

(1,500 meters) x (1 sec / 330 meters) = (4 and 18/33) seconds

                                                                 (4.55 sec, rounded)

8 0
4 years ago
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A particle travels along a straight line with a velocity v = (12 - 3t) m/s, where t is in seconds. When t = 1 s, the particle is
Simora [160]

Answer:

(1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

Explanation:

Given that,

Velocity = (12-3t^2) m/s

When t = 1 s, the particle is located 10 m to the left of the origin.

We need to calculate the acceleration at t = 4 sec

Using formula of acceleration

a=\dfrac{dv}{dt}

Put the value of v

a=\dfrac{d}{dt}(12-3t^2)

a=-6t

Put the value of t

a=-6\times4

a=-24\ m/s^2

The displacement from t = 0,t = 10 s, and the distance the particle travels during this time period.

We need to calculate the distance

Using formula of distance

ds=v\ dt

\int_{-10}^{s}=\int_{1}^{t}{v}dt

Put the value of v

\int_{-10}^{s}=\int_{1}^{t}{ (12-3t^2)}dt

s+10=12t-t^3-11

s=12t-t^3-21

At t = 0,

s_{t=0}=-21

At t = 10,

s_{t=10}=12\times10-10^3-21

s_{t=10}=-901

The displacement is

\Delta s=-901-(-21)

\Delta s=-880\ m

The distance at t= 2 sec

s_{t=2}=12\times2-2^3-21

s_{t=2}=-5

The total distance will be,

s_{T}=(21-5)+(901-5)

s_{T}=912\ m

(2). We need to calculate the distance at 2 sec

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

s=27\times 2+\dfrac{1}{2}\times6\times(2)^3

s=78\ m

Hence, (1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

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3 years ago
ANSWER ASAP PLEASEEE Kendra wonders what would happen if the oceans did not exist on Earth. Based on her understanding of the oc
Cloud [144]

Answer:

that there would be more clouds.

Explanation:

one of the cycles is precipitation. without water there would be no rain and clouds are what causes the rain to come down

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