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leonid [27]
3 years ago
5

What scale factor will dilate triangle ABC so that it has the same vertices as triangle DEF?

Mathematics
2 answers:
mixer [17]3 years ago
8 0

Answer:

0.5

Step-by-step explanation:

Rainbow [258]3 years ago
5 0

Answer:

answer is 0.5 just got it right

Step-by-step explanation:

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2 × (5 + 5)<br><br> Which of the following describes (5 + 5) in the expression above?
Basile [38]

Answer:

20

Step-by-step explanation:

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(2x+2y=10)+(-x+y=1)
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7 0
4 years ago
What is the equation of a line parallel to y=(3)/(4)x-5 and passes through (12,-2)?
Vika [28.1K]

A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.



Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b

-2 = (3/4)*(12) + b

You'll get b= -11

So the equation of the parallel line intersecting the point given is y= 3/4x -11.

I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.

3 0
2 years ago
A parallelogram has an area of 60 square inches. If the base of the parallelogram is 12 inches, what is the height of the parall
Vikentia [17]
How to find the area of a parallelogram is length times height. 12 times what gets you to 60? 5 does. 12 times 5 is 60.

HEIGHT: 5



8 0
3 years ago
Does the series converge or diverge? If it converges, what is the sum? Show your work. ∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Given the series,

∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1

I think the series is summation from n = 1 to ∞ of -4(-1/2)^(n-1)

So,

∑ − 4 ( − ½ )^(n − 1). From n = 1 to ∞

There are different types of test to show if a series converges or diverges

So, using Ratio test

Lim n → ∞ (a_n+1 / a_n)

Lim n → ∞ (-4(-1/ 2)^(n+1-1) / -4(-1/2)^(n-1))

Lim n → ∞ ((-4(-1/2)^(n) / -4(-1/2)^(n-1))

Lim n → ∞ (-1/2)ⁿ / (-1/2)^(n-1)

Lim n→ ∞ (-1/2)^(n-n+1)

Lim n→ ∞ (-1/2)^1 = -1/2

Since the limit is less than 0, then, the series converge...

Sum to infinity

Using geometric progression formula

S∞ = a / 1 - r

Where

a is first term

r is common ratio

So, first term is

a_1 = -4(-½)^1-1 = -4(-½)^0 = -4 × 1

a_1 = -4

Common ratio r = a_2 / a_1

a_2 = 4(-½)^2-1 = -4(-½)^1 = -4 × -½ = 2

a_2 = 2

Then,

r = a_2 / a_1 = 2 / -4 = -½

S∞ = -4 / 1--½

S∞ = -4 / 1 + ½

S∞ = -4 / 3/2 = -4 × 2 / 3

S∞ = -8 / 3 = -2⅔

The sum to infinity is -2.67 or -2⅔

Check attachment for better understanding

3 0
4 years ago
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