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3 years ago

Y = 3x. How do you graph it???

Mathematics

2 answers:

DIA [1.3K]3 years ago

8 0

Answer:

(0, 0) and (1, 3)

happy to help!

lesya [120]3 years ago

5 0

Answer:

If you go to desmos.com, select the graphing calculator, and enter in y = 3x you should be able to see how it's graphed! Hope this helps!

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Round 463,462 to the nearest ten thousand

zhenek [66]

460,000 is the answer

7 0

3 years ago

H. Four businessman invested a sum of Rs.

balandron [24]

Answer:

The answers are in solutions.

Step-by-step explanation:

Four businessmen invested a sum of Rs. 250,000 in the ratio of 3:5:7:10 to start a new business.

(i) The amount invested by each businessman is;

1^st businessman invested:

$\frac{3}{25} * 250,000 =$ Rs. 30,000

2^nd businessman invested:

$\frac{5}{25} * 250,000$ = Rs. 50,000

3^rd businessman invested:

$\frac{7}{25} *250,000$ = Rs. 70,000

4^th businessman invested:

$\frac{10}{25} *250,000$ = Rs. 100,000

If they gained Rs. 50,000

(ii) The profit each one of them got is;

1^st businessman got:

$\frac{3}{25} * 50,000$ = Rs. 6,000

2^nd businessman got:

$\frac{5}{25} *50,000$ = Rs. 10,000

3^rd businessman got:

$\frac{7}{25} *50,000$ = Rs. 14,000

4^th businessman got:

$\frac{10}{25} *50,000$ = Rs. 20,000

8 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

Hence, the theorem that compares both triangles is the SAS theorem

4 0

2 years ago

4.3-4.4 section of pre-calculus problem in link please also tell how you got your answer if can .

Tanya [424]

Answer:

the image os not clear mate sorry

7 0

3 years ago

Solve: |x+2|=3 Can someone explain how to do this

katovenus [111]

Hey there!

ORIGINAL EQUATION:
|x + 2| = 3

TRANSLATE:

x + 2 = 3 or x + 2 = -3

SOLVING for: x + 2 = 3

SUBTRACT 2 to BOTH SIDES

x + 2 - 2 = 3 - 2

CANCEL out: 2 - 2 because it give you 1

KEEP: 3 - 2 because help solve for the current x-value

NEW EQUATION: x = 3 - 2

SIMPLIFY IT!
x = 1

Thus, your answer is: x = 2

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

SOLVING for: x + 2 = -3

SUBTRACT 2 to BOTH SIDES

x + 2 - 2 = -3 - 2

CANCEL out: 2 - 2 because it give you 0

KEEP: -3 - 2 because it help solve for the current x-value

NEW EQUATION: x = -3 - 2

SIMPLIFY IT!
x = -5

Thus, your answer is: x = -5

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

Therefore, your answer is: x = 1 or x = -5

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

6 0

2 years ago