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ziro4ka [17]
3 years ago
14

Y = 3x. How do you graph it???

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

(0, 0) and (1, 3)

happy to help!

lesya [120]3 years ago
5 0

Answer:

If you go to desmos.com, select the graphing calculator, and enter in y = 3x you should be able to see how it's graphed! Hope this helps!

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Answer:

1.5

Step-by-step explanation:

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Problem #4, solve for X
RideAnS [48]

Answer:

I am not 100% sure, however 6x-8=10 add 8 to both sides then youĺl get 6x=18 you divide 6 on both sides, then x will = to 3. I hope this helps

8 0
3 years ago
A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro
olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of P(A\cap B\cap C\cap D).

If two events X and Y are independent, then

P(X\cap Y)=P(X)\times P(Y)

Assume the probability of one part working does not depend on the functionality of any of the other parts.

P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)

Substitute the given values.

P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92

P(A\cap B\cap C\cap D)=0.7559226

P(A\cap B\cap C\cap D)\approx 0.756

Therefore, the probability that the machine works properly is 0.756.

7 0
3 years ago
Help? Statistics...
BartSMP [9]

On your calculator, use the normalcdf() function, enter the Lower Limit, Upper Limit, Mean, and Standard deviation.

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Enter normalcdf(0, 13.5, 13.56, 2.24) in a calculator and the output result is the answer.

7 0
3 years ago
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PLEASE HELP MEEE!! ASAP! I will mark brainliest
Free_Kalibri [48]

Answer:

The last 1 (D)

Step-by-step explanation:

The lines have to be straight nd have to pass through the origin

7 0
2 years ago
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