We have two formulas:
Adult tickets plus Student tickets = 550 tickets or A + S = 550
and
Adult tickets times $20 plus Student ticket times $10 = $7500 or
(A * 20) + (S * 10) = 7500
First let's get rid of one of the variables by re-balancing the simplest formula
A+S = 550
A+S-A = 550-A
S = 550-A
Now we can restate the second formula replacing "S" with it's equivalent "550-A"
(A * 20) + (S * 10) = 7500
(A * 20) + ((550-A) *10) = 7500
Then do the multiplication
20A + 5500 - 10A = 7500
and simplifiy
20A + 5500 - 5500 - 10A = 7500 - 5500
20A - 10A = 2000
10A = 2000
A = 200
S = 550 - 200 = 350
Now we should test the answers to be sure our work
is correct:
200 Adult tickets times $20 = $4000
350 Student tickets times $10 = $3500
$4000 + $3500 = 7500
Answer:
Adult ticket: $7
Child ticket: $2
Step-by-step explanation:
Set up a system of equations where a represents the cost of one adult ticket and c is the cost of one child ticket:
2a + 3c = 20
a + 4c = 15
Solve by elimination by multiplying the bottom equation by -2:
2a + 3c = 20
-2a -8c = -30
Add them together:
-5c = -10
c = 2
Now, we can plug in 2 as c to find the value of a:
2a + 3c = 20
2a + 3(2) = 20
2a + 6 = 20
2a = 14
a = 7
Answer:
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Step-by-step explanation:
Let the line is
where
is slope and
is
.
The line is parallel to
, slope of both the lines will be same.
Find the slope of 
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Slope of line
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So the line will be 
It passes through
.
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Hence the line is 
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