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GrogVix [38]
3 years ago
11

What is the value of b? 50 points in it for you plus a thanks, 5 star and brainliest.

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

Answer:

50

Step-by-step explanation:

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The polynomial y = x2 - 5x + 4 has a repeated factor. (It may help to graph the equation.)
joja [24]
SOLUTION:

y = x^2 - 5x + 4

y = x^2 - 4x - x + 4

y = x ( x - 4 ) - ( x - 4 )

y = ( x - 4 ) ( x - 1 )

ANSWER:

Therefore, the answer is:

A. True.

Hope this helps! :)
Have a lovely day! <3
5 0
3 years ago
There are 15 copies of a popular cd left to be sold in the store this is between 1% and 1.5% of the original number of copies of
Triss [41]

Answer: The original number of CDs is between 1000 and 1500.

Step-by-step explanation:

Since we have given that

Number of copies of a popular CD left to be sold in the store = 15

According to question, this is between 15 and 1.5% of the original number of copies of the CD in the store.

Let the original number of copies of the CD in the store be 'x'.

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1\%\ of\ x=15\\\\\frac{1}{100}\times x=15\\\\x=15\times 100\\\\x=1500

Or if 15 is equal to 1.5% of the original number of copies of the CD, it becomes

1.5\%\ of\ x=15\\\\\frac{1.5}{100}\times x=15\\\\\frac{15}{1000}x=15\\\\x=\frac{15\times 1000}{15}\\\\x=1000

Hence, the original number of CDs is between 1000 and 1500.

3 0
3 years ago
Write the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8).
mina [271]
Notice the picture below

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5 0
2 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
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Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
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Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
3 years ago
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Find the midpoint of (-3,7) and (-9,1).​
Temka [501]

Answer:

(-6, 4)

Step-by-step explanation:

3 0
3 years ago
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