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3 years ago

What is the value of b? 50 points in it for you plus a thanks, 5 star and brainliest.

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

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Determine the intercepts of the line 20 POINTS<br> y-intercept(____,____)<br> x-intercept(____,____)

Ivenika [448]

Answer:

y-intercept(0,0.4)

x-intercept(0.3 ,0)

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3 years ago

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State whether the following statements are true or false, and explain your reasoning.

Masja [62]

Answer:

Step-by-step explanation:

a) A square is a rectangle. True

Reason: Property of Rectangle: (i) Opposite sides are equal and parallel. (ii) Each angle is 90 (iii) Diagonals are equal and bisect each other.

A square hold all these properties. A square is a rectangle.

b) A polygon with 21 sides has 432 possible diagonals. False

Reason: Number of diagonals of a polygon = $\frac{n(n-3)}{2}$

n --> number of sides of a polygon.

= $\frac{21*18}{2}$ = 189 diagonals

c) All three angles in an Isosceles triangle are equal. False

Reason: In an isosceles triangle, two angles are equal.

If three angles are equal, then that is an equilateral triangle.

d) The measures of the exterior angles of a nonagon, a nine-sided figure, have a sum of 360°. True.

Reason: The sum of measures of the exterior angles of any polygon is 360

6 0

3 years ago

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Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh

fredd [130]

With

$\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k$

we have

$\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

The vector field evaluated over this parameterization is

$\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k$

so the line integral is

$\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

$=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4$

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3 years ago

A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and

gayaneshka [121]

Answer:

$(832.156, \ 847.844)$

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, $\overline x = 840$

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}$

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

$E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

$(840-7.844 , \ 840+7.844)$

$(832.156, \ 847.844)$

4 0

2 years ago

Please help me!!!!! Im confused help with these 3 and tell me how u got it

AnnZ [28]

Hi

45. A) x

46. B) 18

47. D) 1/27

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2 years ago