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Zarrin [17]
3 years ago
6

plss help asap Around which line would the following cross-section need to be revolved to create a sphere? circle on a coordinat

e plane with center at 1 on the x-axis and a radius of 1 y = x y-axis x = 1 y = 1
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
4 0

Answer:

The correct option is;

x = 1

Step-by-step explanation:

The parameters given are;

Location of circle center = 1 on the x axis

Radius of circle = 1

Required operation on circle = Revolving to create a sphere

To form a spherical shape by the rotation of a circular figure involves rotating the circular figure about a line passing through the center of the circle

Therefore, to form a sphere, the circle should be about a line that passes through x = 1

Hence, the circle should be rotated about the line x = 1.

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What is the slope of -2x + 4y = 12 ?
Daniel [21]

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Slope:  1/4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Int he figure below find AC
Ahat [919]

Given :-

  • Two triangles with their two angles equal .

To Find :-

  • Measure of AC .

Answer :-

Here in ∆ABC and ∆EDC ,

  • \angle CAB = \angleCED (given )
  • \angle CBA = \angleCDE (given)

Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,

→ AC/EC = BC/DC

→ AC/9 = 8/12

→ AC = 8/12 * 9

→ AC = 6

<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>

I hope this helps.

7 0
3 years ago
In rhombus ABCD, the diagonal line AC and line BD intersect at E. If AE=5 and BE = 12, what is the length of line AB?
Reika [66]
From a formula located here:
http://www.1728.org/quadltrl.htm
we see that
<span>4 • Side² = Long Diagonal² + Short Diagonal²
Long Diagonal = 24
Short Diagonal = 10
</span><span>4 • Side² = 24^2 + 10^2 </span>
<span>4 • Side² = 576 + 100
</span><span>4 • Side² = 676
</span><span><span>Side²</span> = 169
Side (or line AB) = 13

</span>



8 0
3 years ago
I need help ASAP please
Rom4ik [11]

Answer:

Use photomath

Step-by-step explanation:

sorry it doesnt answer your question but just use it it's free and great

7 0
3 years ago
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