K (Q1) (Q2)/d^2 =
k : coulumb constant
Q1 : Charge on object 1
Q2 : Charge on object 2
d : distance between two charged object
Answer:
13
Explanation:
13.0120481928 it is the distance
Answer:
The acceleration of the skateboard is -9.65 m/s².
Explanation:
Given that,
Mass of teenager = 72 kg
Force
Mass of skateboard = 2.8 kg
Suppose, the determine the numerical value for the magnitude of the acceleration of skateboard
We need to calculate the acceleration of skateboard
Using balance equation
Put the value into the formula
Hence, The acceleration of the skateboard is -9.65 m/s².
Answer:
12824.74 N
Explanation:
mass of bullet, m = 21 g = 0.021 kg
distance, s = 114 cm = 1.14 m
final velocity, v = 1180 m/s
initial velocity, u = 0
Let F be the force .
By use of work energy theorem
Work done = change in kinetic energy
F x s = 1/2 m v² - 1/2 mu²
F x 1.14 = 0.5 x 0.021 x 1180 x 1180
F = 12824.74 N
Answer:
n = 1.76
Explanation:
According to the rule of ( n1 sin theta1 = n2 sin theta2 )
we know both angles so we insert them to the law and apply n1 = 1
so 1/2 = n2 sin 62 and we get the final answer