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Allisa [31]
3 years ago
6

Which statement best describes the density of the outer planets?

Physics
2 answers:
ICE Princess25 [194]3 years ago
7 0
Yes it is the only planet
gavmur [86]3 years ago
5 0

Answer:

Saturn is mainly composed of the lightest two gases known, hydrogen and helium. It is the only planet in our solar system whose density is less than water.

Explanation:

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If the Velocity of the body<br> is increased to 3v, determine the kinetic energy
Rom4ik [11]

ANSWER; KE=5mv^2 so it is proportional to v^2.

Explanation:So if you triple the velocity you are replacing v with 3v. Then you get (3v)^2=9v^2.

7 0
3 years ago
How much mass energy could be obtained from the complete conversion of a 235 g hamburger?
Radda [10]
E = mc²
E = 0.235 kg · (3×10⁸ m/s)² = 0.235 · 9×10¹⁶  kg·m/s²
E = 2.115×10¹⁶ J
The answer is d) 2.12×10¹⁶ J
8 0
3 years ago
Suppose that we replace the aluminum with a mystery metal and repeat the experiment in the video. As in the video, the mass of t
soldi70 [24.7K]

Answer:

a) three times greater

Explanation:

Remember the heat capacity is the necessary heat to increase the temperature 1 ºC to an specific mass of the substance, in this case since the water and the metal have the same mass, is easier to compare just the neccesary heat.

Since water increases 20 ºC and the metal 60 ºC, it was neccesary 3 times of the quantity of heat to the same amount of mass of the two different susbtances.

Hope it was useful

5 0
3 years ago
Read 2 more answers
4. A stone is dropped from the fifth floor of a building from a height 14 m. How long would it take
aleksklad [387]

Answer:

1.690308509s

Explanation:

v²=u²+2as

v²=0²+2(9.8)(14)

v²=274.4

∴v=16.56502339m/s

v=u+at

16.56502339=0+9.8t

∴t=1.690308509s

6 0
3 years ago
A bullet of mass of 0.05kg is fired horizontally into a 10 kg block which is free to move with a velocity of 0.5mls after impact
Fiesta28 [93]

It is given that :

Mass of bullet, m_{1} = 0.05 Kg

Mass of block, m_{2} = 10 kg

velocity after impact, v = 0.5 m/s

Let v_{1}  is the velocity with which the bullet is fired.

Using law of conservation of momentum :

m_{1}v_{1}+m_{2}v_{2} = (m_{1}+m_{2})v

0.05 \times v_{1}+0=(0.05+10) \times 0.5\ (since, the block is at rest)

0.05\times v=10.05\times 0.5

m_{2}=100.5\ m/s

5 0
3 years ago
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