Answer:
Mass of Jupiter = 4.173×10^15kg
Explanation:
Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:
T^2 = GM/4 pi × r^3
Where G = universal gravitational constant
r = radius
M = masd of jupiter
Rearranging the formular to make M the subject of formular
T^2 × 4 pi = G M × r^3
(T^2 × 4 pi) / (G× r^3) = M
(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3
M = 19.32 /6.672×10^-11)(4.11×10^8)^3
M = 19.32 / 4.63 ×10^15
M = 4.173×10^15kg
Answer:
option (b)
Explanation:
mass of proton, mp = m
mass of deuteron, md = 2m
charge on proton, qp = q
charge on deuteron, qd = q
The magnetic force on the charged particle when it is moving is given by
F = q v B Sinθ
where, θ is the angle between the velocity and magnetic field.
Here, θ = 90°
Let v is the velocity of both the particle when they enters in the magnetic field.
The force on proton is given by
Fp = q x v x B ...... (1)
The force on deuteron is
Fd = q x v x B .... (2)
Divide equation (1) by equation (2)
Fp / Fd = 1
Thus, the ratio of force on proton to the force on deuteron is 1 : 1.
Thus, option (b) is correct.
I believe that the correct given values are:
density = 755 kg/m^3
volume = 640 cm^3
First let us convert volume to m^3 units.
volume = 640 cm^3 * (1 m / 100 cm)^3 = 6.4 x 10^-4 m^3
so the mass is:
mass = 755 kg/m^3 * (6.4 x 10^-4 m^3)
<span>mass = 0.4832 kg = 483.2 g</span>
Answer
given,
watermelon blown into three pieces
two pieces of mass m
both pieces speed = v = 31 m/s
mass of third piece = 3 m
using conservation of mass
velocity of third component
angle
