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ZanzabumX [31]
4 years ago
14

Leia is presenting her project about gravity to her class. She says that both mass and distance affect how strong the gravitatio

nal force is, and that as the
distance between two objects increases, so does the gravitational force. Is Leia correct?
Yes, all of her statements are true.
No, because distance does not actually affect gravitational force.
No, because mass does not actually affect gravitational force.
No, because as distance increases, gravitational force decreases.

please help asap!!
Physics
1 answer:
DaniilM [7]4 years ago
5 0

Answer:

No, because as distance increases, gravitional force decreases.

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A person investing p at a certain rate of simpl interest after 1 2 and3 years it amounted to 1.5 p 2.5 p respectively what will
Ulleksa [173]

Answer: It will amount to 11p after 20 years.

Explanation:

Formula :

Simple interest = Principal x rate x Time              (i)

Amount = Principal + Interest

Amount = Principal +   Principal x rate x Time

Amount =  Principal (1+  rate x Time)                       (ii)

Given: Principal = p

After 1 year , amount = 1.5p

After 3 years , amount = 2.5p

From (ii)

1.5p = p (1+r)\\\\\Rightarrow\ 1.5=1+r\\\\\Rightarrow\ 0.5= r\\\\\Rightarrow r= 0.5

Amount after 20 years = p(1+ 0.5 x 20) = p(1+10)=11p

It will amount to 11p after 20 years.

7 0
3 years ago
A.
lorasvet [3.4K]

Answer:

A) Option 1 is the correct answer.

B) Option 4 is the correct answer.

Explanation:

A) Weight of liquid = 7 N

    Volume of liquid = 1 L = 0.001 m³

    Specific weight =  \frac{7}{0.001}=7000N/m^3

    Density = \frac{7000}{9.81}=713.5kg/m^3

    Specific gravity = \frac{713.5}{1000}=0.7135

    Option 1 is the correct answer.

B) The Stokes(St) is the cgs physical unit for kinematic viscosity, named after George Gabriel Stokes.

We have

             1 St = 10⁻⁴ m²/s

    Option 4 is the correct answer.        

7 0
3 years ago
Relativistic kinetic energy is conserved in all reference frames. True O False
Free_Kalibri [48]

Answer:

i think it is true

Explanation:

7 0
3 years ago
Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
4 years ago
What did Rutherford​ model of tje atom include that thompson model did not leave
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Rutherford discovered the half life
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