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Bond [772]
3 years ago
15

If you stood on a planet having a mass four times higher than Earth's mass, and a radius two times 70) lon longer than Earth's r

adius, you would weigh:________
A) four times more than you do on Earth.
B) two times less than you do on Earth.
C) the same as you do on Earth
D) two times more than you do on Earth.
Physics
1 answer:
BigorU [14]3 years ago
7 0

CHECK COMPLETE QUESTION BELOW

you stood on a planet having a mass four times that of earth mass and a radius two times of earth radius , you would weigh?

A) four times more than you do on Earth.

B) two times less than you do on Earth.

C) the same as you do on Earth

D) two times more than you do on Earth

Answer:

OPTION C is correct

The same as you do on Earth

Explanation :

According to law of gravitation :

F=GMm/R^2......(a)

F= mg.....(b)

M= mass of earth

m = mass of the person

R = radius of the earth

From law of motion

Put equation b into equation a

mg=GMm/R^2

g=GMm/R^2

g=GM/R^2

We know from question a planet having a mass four times that of earth mass and a radius two times of earth radius if we substitute we have

m= 4M

r=(2R)^2=4R^2

g= G4M/4R^2

Then, 4in the denominator will cancel out the numerator we have

g= GM/R^2

Therefore, g remain the same

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Answer:

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Answer;

The above statement is false

Explanation;

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A jet airliner moving initially at 889 mph
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Answer:

1500 mph

Explanation:

Take east to be +x and north to be +y.

The x component of the velocity is:

vₓ = 889 cos 0° + 830 cos 59°

vₓ = 1316.5 mph

The y component of the velocity is:

vᵧ = 889 sin 0° + 830 sin 59°

vᵧ = 711.4 mph

The speed is found with Pythagorean theorem:

v² = vₓ² + vᵧ²

v² = (1316.5 mph)² + (711.4 mph)²

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Rounded to two significant figures, the jet's speed relative to the ground is 1500 mph.

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Andreyy89

Displacement is B) the shortest distance between the starting point and the ending point of a motion

Explanation:

Displacement is a vector quantity; it is a vector connecting the initial position to the final position of motion of an object.

Since it is a vector, it has both a magnitude and a direction:

  • The magnitude of the displacement is the length of the vector, therefore it corresponds to the shortest distance in a  straight line between the starting point and the ending point of the motion
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Therefore, the correct answer is

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Note that displacement is very different  from distance. Consider for example an object moving in a circle, returning to its initial position: in this case, the distance covered by the object is not zero (it is the length of the circle), however the  displacement is zero, because the initial position corresponds to the ending position.

Learn more about distance and displacement:

brainly.com/question/3969582

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