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miv72 [106K]
3 years ago
13

Find the equation of this line.HELP​

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

Step-by-step explanation:

(5,4) ;  (-3, -2)

Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-2-4}{-3-5}\\\\=\frac{-6}{-8}\\\\=\frac{3}{4}

(5,4) & m = (3/4)

y -y1 = m(x-x1)

y - 4 = (3/4)(x - 5)

y-4=\frac{3}{4}x-\frac{3}{4}*5\\\\y-4=\frac{3}{4}x-\frac{15}{4}\\\\y=\frac{3}{4}x-\frac{15}{4}+4\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{4*4}{1*4}\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{16}{4}\\\\y=\frac{3}{4}x+\frac{1}{4}

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Which system of inequalities does the graph represent? Which test point satisfies both of the inequalities in that system?
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Answer:

Ok so its -3;3

Step-by-step explanation:

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3 years ago
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Solve x ^3 = 125 for x. You can see the graph of the equation y = x ^3 - 125 below.
Harrizon [31]
\bf x^3=125\implies x=\sqrt[3]{125}\implies x=5
5 0
4 years ago
Solve : 1+8n=13+6n help???
ANTONII [103]
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4 0
3 years ago
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Can anyone please help
shusha [124]

\text{Hi there! :)}

\large\boxed{f'(2) = -\frac{16}{27} }

f'(x) = \frac{(5 + x^{2} )(-2x) - (7 - x^{2} )(2x)}{(5+x^{2})^{2}  } \\\\f'(x) = \frac{-10x-2x^{3}- 14x + 2x^{3} }{(5+x^{2})^{2} } \\\\f'(x) = \frac{-24x}{(5+x^{2})^{2}  }\\\\ \text{Solve for the derivative at f'(2) using substitution:}\\\\f'(2) = \frac{-24(2)}{(5+2^{2})^{2}   } \\\\f'(2) = \frac{-48}{81} \\\\\text{Simplify:}\\\\f'(2) = -\frac{16}{27}

8 0
3 years ago
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How do you solve <br>2v+18=16-4(v+7)
Andreyy89
2v + 18 = 16 - 4(v + 7)

Simplify by removing the parenthesis.

2v + 18 = 16 - 4v - 28

Now, simply add 4v to both sides.

2v + 4v + 18 = 16 - 28

Simplify.

6v + 18 = -12

Now, subtract 18 from both sides.

6v = -12 - 18

Simplify.

6v = -30

Finally, divide both sides by 6.

6v ÷ 6 = 30 ÷ 6

Simplify.

v = 5

~Hope I helped!~

4 0
3 years ago
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