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EleoNora [17]
3 years ago
12

A. Only similar

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

Neither similar nor congruent.

TEA [102]3 years ago
4 0

Answer:Bote

Step-by-step explanation: both

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A wire is in the shape of a rectangle of length 14cm. Find its breadth if the same wire is re- bent into a square of side 13cm.
lara [203]
Length= 40cm

Breadth= 22cm

Perimeter of the rectangle= Length of the wire

=2(l+b)= 2(40cm + 22cm)

=2\times62cm = 124cm

Now, the wire is rebent into a square.

Perimeter= 124cm

4\times side=124

Therefore side= \frac{124}{4}cm= 31cm

So, the measure of each side= 31cm

Area of rectangular shape= l\times b

=40cm\times22cm

=880cm^2

Area of a square shape= \left(Side\right)^2

=\left(31\right)^2=961cm^2

Since 961cm^2\ >\ 880cm^2

Hence, the square encloses more area.
7 0
2 years ago
Read 2 more answers
Puzzle in the picture. explain how you did it, the answer should be 23.
Ksju [112]

Answer:

Bro you have got the answer as 17 I don't know how

Step-by-step explanation:

Please mark me as brainliest

6 0
2 years ago
PLEASE HELP A flight across the US takes longer east to west then it does west to east. This is due to the plane having a headwi
il63 [147K]
To solve our questions, we are going to use the kinematic equation for distance: d=vt
where
d is distance 
v is speed  
t is time 

1. Let v_{w} be the speed of the wind, t_{w} be time of the westward trip, and t_{e} the time of the eastward trip. We know from our problem that the distance between the cities is 2,400 miles, so d=2400. We also know that the speed of the plane is 450 mi/hr, so v=450. Now we can use our equation the relate the unknown quantities with the quantities that we know:

<span>Going westward:
The plane is flying against the wind, so we need to subtract the speed of the wind form the speed of the plane:
</span>d=vt
2400=(450-v_{w})t_{w}

Going eastward:
The plane is flying with the wind, so we need to add the speed of the wind to the speed of the plane:
d=vt
2400=(450+v_{w})t_{e}

We can conclude that you should complete the chart as follows:
Going westward -Distance: 2400 Rate:450-v_w Time:t_w
Going eastward -Distance: 2400 Rate:450+v_w Time:t_e

2. Notice that we already have to equations:
Going westward: 2400=(450-v_{w})t_{w} equation(1)
Going eastward: 2400=(450+v_{w})t_{e} equation (2)

Let t_{t} be the time of the round trip. We know from our problem that the round trip takes 11 hours, so t_{t}=11, but we also know that the time round trip is the time of the westward trip plus the time of the eastward trip, so t_{t}=t_w+t_e. Using this equation we can express t_w in terms of t_e:
t_{t}=t_w+t_e
11=t_w+t_e equation
t_w=11-t_e equation (3)
Now, we can replace equation (3) in equation (1) to create a system of equations with two unknowns: 
2400=(450-v_{w})t_{w}
2400=(450-v_{w})(11-t_e) 

We can conclude that the system of equations that represent the situation if the round trip takes 11 hours is:
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

3. Lets solve our system of equations to find the speed of the wind: 
2400=(450-v_{w})(11-t_e) equation (1)
2400=(450+v_{w})t_{e} equation (2)

Step 1. Solve for t_{e} in equation (2)
2400=(450+v_{w})t_{e}
t_{e}= \frac{2400}{450+v_{w}} equation (3)

Step 2. Replace equation (3) in equation (1) and solve for v_w:
2400=(450-v_{w})(11-t_e)
2400=(450-v_{w})(11-\frac{2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{4950+11v_w-2400}{450+v_{w}} )
2400=(450-v_{w})( \frac{255011v_w}{450+v_{w}} )
2400= \frac{1147500+4950v_w-2550v_w-11(v_w)^2}{450+v_{w}}
2400(450+v_{w})=1147500+2400v_w-11(v_w)^2
1080000+2400v_w=1147500+2400v_w-11(v_w)^2
(11v_w)^2-67500=0
11(v_w)^2=67500
(v_w)^2= \frac{67500}{11}
v_w= \sqrt{\frac{67500}{11}}
v_w=78

We can conclude that the speed of the wind is 78 mi/hr.
6 0
3 years ago
For each diagram, describe a translation, rotation, or reflection that takes line ℓ to line ℓ′. Then plot and label A′ and B′, t
inn [45]

Answer:

  1. translate down 3
  2. reflect across the horizontal line through A

Step-by-step explanation:

1. There are many transformations that will map a line to a parallel line. Translation either horizontally or vertically will do it. Reflection across a line halfway between them will do it, as will rotation 180° about any point on that midline.

In the first attachment, we have elected to translate the line down 3 units.

__

2. Again, there are many transformations that could be used. Easiest is one that has point A as an invariant point, such as rotation CW or CCW about A, or reflection horizontally or vertically across a line through A.

Any center of rotation on a horizontal or vertical line through A can also be used for a rotation that maps one line to the other.

In the second attachment, we have elected to reflect the line across a horizontal line through A.

6 0
3 years ago
There are 3 balls in a hat; one with the number 1 on it, one with the number 6 on it, and one with the number 7 on it. You
V125BC [204]

Answer:

coin: ball:

1

head -- 6

7

1

tail -- 6

7

6 0
3 years ago
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