The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
brainly.com/question/1770447
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Answer: Is 5.7
Step-by-step explanation:
C=4x4=16 A=4x4=16
16+16=32
32^=5.7
Distance:
subtract (5,2)-(2,6) = (3,-4)
Compute the length (Pythagoras): sqrt( 3^2 + (-4)^2 ) = sqrt(25)=5
So, C!
x
(15) sin 30.5 = ------ (15)
15
(15) sin 30.5 = x
Plug this part into a calculator.
7.61 = x
Area of a triangle: 1/2bh
1/2 (7.61)(13)
3.805(13)
49.469
49.47 un² is your final answer since you are supposed to round to the tenths place. I hope this helps.
