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Gre4nikov [31]
3 years ago
5

F(n) = -11 + 22(n = 1) Complete the recursive formula of f(n). f(1) = f(n) = f(n - 1)+

Mathematics
1 answer:
Maslowich3 years ago
7 0

Answer:

f(n)=f(n-1)+22.

Step-by-step explanation:

Note: In the given function it should be (n-1) instead of (n=1).

Consider the given function is

f(n)=-11+22(n-1)

It is the explicit form of an A.P.

For n=1,

f(1)=-11+22(1-1)=-11+0=-11

For n=2,

f(2)=-11+22(2-1)=-11+22=11

Common difference is  

d=a_2-a_1=11-(-11)=11+11=22

The recursive formula of an A.P. is

f(n)=f(n-1)+d

Substitute d=22 in the above formula.

f(n)=f(n-1)+(22)

f(n)=f(n-1)+22

Therefore, required recursive formula is f(n)=f(n-1)+22.

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a)

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(b)

Proof by Contrapositive:

Assumed statement: Let n be an integer such that n is not odd (i.e. n is an even integer)

Proven Statement: n² is not odd (i.e n² is even)

Proof -

Let n is even

⇒n = 2m

⇒n² = (2m)² = 4m²

⇒n² is even

Hence proved.

Proof by Contradiction:

Assumed statement: Let n be an integer such that n² be odd.

Proven Statement:  suppose that n is not odd (i.e n is even)

Proof -

Let n² is odd

⇒n² is even

⇒n² = 2m

⇒2 | n²

⇒2 | n

⇒n = 2x

⇒ n is even

Contradiction

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