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IgorLugansk [536]
2 years ago
14

Identify the constant of proportionality for each direct variation below.

Mathematics
1 answer:
andriy [413]2 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

The equation of 2 quantities in direct proportion is

y = kx ← k is the constant of proportionality

1

y = - 4x ← in standard form

with k = - 4

2

\frac{y}{x} = 2 ( multiply both sides by x )

y = 2x ← in standard form

with k = 2

3

\frac{x}{y} = 3 ( multiply both sides by y )

x = 3y ( divide both sides by 3 )

\frac{1}{3} x = y ← in standard form

with k = \frac{1}{3}

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Can someone graph this quick plsssss
melomori [17]

Answer:

x = 0.529 and y = 3.882

Step-by-step explanation:

The given equations are :

y=\dfrac{5}{3}x+3\ ......(1)\\\\y=\dfrc{1}{3}x-3\ .......(2)

We need to solve the equations by graphing.

The attached figure shows the solution of the given equations. We can see that, the intersecting points are :

x = 0.529 and y = 3.882

Hence, this is the required solution.

6 0
3 years ago
PLS HELP
4vir4ik [10]

Answer: 2/3

Step-by-step explanation:

14 is 2/3 of 21 so 2/3 cup per loaf

5 0
3 years ago
Read 2 more answers
i used the answer key to get my answer and checked it with my dumb useless teacher and it’s right but, he won’t tell me how to g
gizmo_the_mogwai [7]
You multiply it with the same number you use for the denominator.
in this case 3/4 and 7/10
you find the LCM of the denominator is 20
so for 4 to become 20 you multiply by 5 then for the numerator 3 also multiply by 5, so you get 15/20
its the same also with 7/10, you multiply both the numerator and the denominator by 2 and get 14/20
hope it help... :)




7 0
3 years ago
An ice chest contains cans of apple juice, cans of grape juice, cans of orange juice, and cans of mango juice. Suppose that you
mel-nik [20]

Answer:

4.9%

Step-by-step explanation:

This question is incomplete. However; it can be found on search engines. The complete question is  as follows :

An ice chest contains cans of six apple juice, eight cans of grape juice, four cans of orange juice, and two cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of grape juice.

Solution :

In an ice chest there are different cans of juice. Among them

Number of cans of apple juice = 6

Number of cans of grape juice = 8

Number of cans of orange juice = 4

Number of cans of mango juice = 2

Total number of cans of juice = 6 + 8 + 4 + 2 = 20

Let A, B and C are the event of selecting of three cans.  The events A, B and C are dependent.

Probability of selecting three cans of juice

P = \frac{\text{number of grape cans}}{\text {total number of cans}}

P (A) = \frac{8}{20}

P (B) = \frac{7}{19}

P (B) = \frac{6}{18}

P = \frac{8}{20} × \frac{7}{19} × \frac{6}{18}

  = \frac{336}{6840}

  = 0.049 or 4.9%

Probability of selecting three cans of grape juice is 4.9%

5 0
3 years ago
What is the approximate length of RP? Round to the
suter [353]
6.1 units is the correct answer
5 0
3 years ago
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