Answer:
Step-by-step explanation:
Answer:
f(-2/3) = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x + 1
f(-2/3) is x = -2/3
<u>Step 2: Evaluate</u>
- Substitute: f(-2/3) = 3(-2/3) + 1
- Multiply: f(-2/3) = -2 + 1
- Add: f(-2/3) = -1
I’m having trouble reading your equations is it
(2i-1/x+1)^(4)-13(x-1/x+1)^(2)+36=0
I just want to confirm before doing it just comment if that’s the correct equation.
Answer:
Step-by-step explanation:
- 7 + 3x - 12x = 3x + 1
- 7 - 9x = 3x + 1
- 3x + 9x = 7 - 1
- 12x = 6
- x = 6/12
- x = 1/2
It has one solution
Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
