Answer:
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
<em>
</em>
Step-by-step explanation:
Given the simultaneous equation
2x- 6y=6 ... 1
6x - 4y = 2 ... 2
To eliminate a variable, we have to make the coefficient of one of the variable to be the same.
Multiply equastion 1 by -3
-6x+18y= -18
6x - 4y = 2
Add the result:
-6x + 6x + 18y-4y = -18+2
18y-4y = -18+2
14y = -18
y = -9/7
Another way is to Multiply the bottom equation by -3/2 then add the equations.
Multiplying equation 2 by -3/2 will give;
6x(-3/2) - 4y(-3/2) = 2(-3/2)
-9x + 6y = -3
Add to equation 1;
2x- 6y=6
-9x + 2x + 0 = -3+6
-7x = 3
x = -3/7
Hence the correct two options are;
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
<em>
</em>
<em></em>
<em></em>
For the answer to the question above, <span>if
a1 = 2,
then
a2 = 3a1 + 1
a3 = 3a2 + 1 = 3
Then, we can finally solve for terms of sequence.
(3a1 + 1) + 1 = 9a1 + 4 = 9(2) + 4 = 22
So the answer to your question is,
</span><span>22, 67, 202, 607
</span>
I hope my answer helped you. Have a nice day!
Answer:25
Step-by-step explanation
5 x 5 = 25. Got this problem correct on Imagine Math.
Answer:
6- 8- 10 triangle with 10 as the hypotenuse
Step-by-step explanation:
In any right triangle the hypotenuse must be the longest side.
This is only true for the 6- 8- 10 with 10 as the hypotenuse.
Also using Pythagoras' identity
6² + 8² = 10²
Answers to the entire test:
Step-by-step explanation:
1. C. a<b
2.A. x >_0
3. A. The product between 3 and a number is greater than 9
4. B. The difference of 16 and the product of 5 and a number is no less than 1
5.B. 6(x-4)<_20
