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3 years ago

Use factoring to solve x^2-2x-35=0

Mathematics

2 answers:

deff fn [24]3 years ago

8 0

Answer:

The solution set of the quadratic equation is

x = {7, -5}

Step-by-step explanation:

Given the quadratic equation

$x^2 - 2x -35 = 0$

We need to factor this equation

So you need two numbers such that

a + b = -2

and

a×b = -35

How about -7 and 5?

-7 + 5 = -2

-2 = -2

and

-7×5 = -35

-35 = -35

(x - 7)(x + 5) = 0

(x - 7) = 0

x = 7

and

(x + 5) = 0

x = -5

Therefore, the solution set of the quadratic equation is

x = {7, -5}

Verification:

Plug 7 into the quadratic equation

$x^2 - 2x -35 = 0 \\\\(7)^2 - 2(7) -35 = 0 \\\\49 - 14 - 35 = 0 \\\\49 - 49 = 0\\\\0 = 0$

Plug -5 into the quadratic equation

$x^2 - 2x -35 = 0 \\\\(-5)^2 - 2(-5) -35 = 0 \\\\25 + 10 - 35 = 0 \\\\35 - 35 = 0\\\\0 = 0$

mrs_skeptik [129]3 years ago

7 0

Answer:

I'm sorry I don't have an answer but for all future math work you should download photomath on your phone it's rly good

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PLEASE HELP!<br><br> Reduce to simplest form.<br> 5/8 - (- 7/2)

Daniel [21]

Answer:

$\huge\boxed{\sf 4\frac{1}{8} }$

Step-by-step explanation:

$\sf =\frac{5}{8} - (-\frac{7}{2} )\\\\Rule : ( - *- = +)\\\\\=\frac{5}{8} +\frac{7}{2} \\\\LCM = 8\\\\\=\frac{5+28}{8} \\\\\=\frac{33}{8} \\\\=4\frac{1}{8}$

$\sf =\frac{5}{8}+ \frac{7}{2} \\\\=\frac{5+28}{8}$

$\sf =\frac{33}{8} \\\\=4\frac{1}{8}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

7 0

3 years ago

Additive inverse of −2, additive identity of −5, additive inverse of 3, multiplicative identity of 19, and multiplicative invers

monitta

Answer:

See Explanation

Step-by-step explanation:

a) Additive inverse of −2

the additive inverse of a number a is the number that, when added to 'a', yields zero. This number is also known as the opposite (number), sign change, and negation.
So the Additive inverse of -2 is 2. ∴ -2+2=0

b) Additive identity of −5

Additive identity is the value when added to a number, results in the original number. When we add 0 to any real number, we get the same real number.
-5 + 0 = -5. Therefore, 0 is the additive identity of any real number.

c) additive inverse of 3

Two numbers are additive inverses if they add to give a sum of zero. 3 and -3 are additive inverses since 3 + (-3) = 0. -3 is the additive inverse of 3.

d). multiplicative identity of 19

an identity element (such as 1 in the group of rational numbers without 0) that in a given mathematical system leaves unchanged any element by which it is multiplied
Multiplicative identity if 19 is 1 only, since 19 x 1 = 19.

e) multiplicative inverse of 7

Dividing by a number is equivalent to multiplying by the reciprocal of the number. Thus, 7 ÷7=7 × 1⁄7 =1. Here, 1⁄7 is called the multiplicative inverse of 7.

d) | 11-5|×|1-5|

| 11-5|×|1-5| ⇒ I6I×I-4I ⇒ 6×4 ⇒ 24

8 0

3 years ago

Can someone please help me?

Lisa [10]

Answer:

Step-by-step explanation:

Using a graphing calculator, the graph shows an almost parabola like shape between 0 and 12

Plus if the width was equal or greater than twelve we would have a 0 or even negative volume which is impossible

7 0

3 years ago

HELP PLS PLS PLS PLS

solmaris [256]

Answer:

The probability of a person going to work by car is 48

And the probability of different way is 52

Step-by-step explanation:

As it's represented in the table above, there are 48 percent employees use cars as their transportation to work, and to find the rest sum all the probability of other transportation together which will give you 52 percent.

5 0

2 years ago

A shop has determined that the number of bottles of water they sell on a summer day is a function of the day’s high temperature,

Alik [6]

Answer:

$T=t+94$

Where T is the hight temperature and t is the day

Explanation:

The table shows that every day the<em> High temperature, T (degrees F) </em>increases 1 unit.

Then, this is a linear function with slope = 1ºF / day.

You can use the point-slope equation to determine the <em>function of the high temperature:</em>

Point-slope equation:

$y-y_1=m(x-x_1)$

Choose any point from the table and m = 1. I will use the first point (1,95)

m = 1

x₁ = 1

y₁ = 95

Substitute:

$y-95=1(x-1)\\\\y=x-1+95\\\\y=x+94$

Make the variables y = T, and x = t:

$T=t+94$

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3 years ago