The solutions and homogeneous mixtures in the given list are:
A. Lead solder, an alloy of tin and lead.
D. Window cleaner, a mixture of ammonia and coloring dissolved in water.
E. Gasoline, a mixture of organic liquids with a fixed composition throughout.
<h3>What is a solution?</h3>
A solution can be defined as a special type of homogeneous mixture that comprises a solute and a solvent.
A homogeneous mixture can be defined as any solid, liquid, or gaseous mixture which has an identical (uniform) composition and properties throughout any given sample of the mixture.
In Science (Physics), all solutions are considered to be a homogeneous mixture because their constituents are uniformly (evenly) distributed.
In conclusion, the solutions and homogeneous mixtures in the given list are:
- Lead solder, an alloy of tin and lead.
- Window cleaner, a mixture of ammonia and coloring dissolved in water.
- Gasoline, a mixture of organic liquids with a fixed composition throughout.
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When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².
<h3>
Frictional force between the block and the horizontal surface</h3>
The frictional force between the block and the horizontal surface is determined by applying Newton's law;
∑F = ma
F - Ff = ma
Ff = F - ma
Ff = 4 - 2(1.2)
Ff = 4 - 2.4
Ff = 1.6 N
When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;
F - Ff = ma
5 - 1.6 = 2a
3.4 = 2a
a = 3.4/2
a = 1.7 m/s²
Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².
Learn more about frictional force here: brainly.com/question/4618599
#1
for the block of mass 5 kg normal force is given as


friction force is given as


Net force is given as


now we know that



#2
Normal force is given as



now we know that


as object moves with constant velocity

now for coefficient of friction we can use



#3
net force upwards is given as

mass is given as

now as per newton's law we can say



#4
As we know that when block is sliding on rough surface
part a)
net force = applied force - frictional force




part b)
for coefficient of friction we can use


here normal force is given as

now we have

#5
if an object is initially at rest and moves 20 m in 5 s
so we can use kinematics to find out the acceleration



now net force is given as


#6
an object travelling with speed 25 m/s comes to stop in 1.5 s
so here acceleration of object is given as


now the force is gievn as


It forces the mercury to rise, being pushed up the tube by pressing down on the dish.
I hope I could help :)
Answer:
Total displacement 155 m
Explanation:
From the question, the formula to apply will be that of cosine rule where:

where
a= 43 m , b=130m and c =? , <C=28° + 90° =118°
Substituting values in the equation as;

