On your first trip to Planet X you happen to take along a 180 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r
1 answer:
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The first thing you should know is that the distance is equal to the speed per time.
Therefore if You walk forward at 1.5 m / s for 8s
d = 1.5t [0,8] s
Your friend decides to walk faster and starts at 2.0 m / s for the first 4 s.
d = 2t [0,4] s
Then she slows down and walks forward at 1.0 m / s for the next 4s
d = t + 4 [4,8] s
Who walked farther?
They both walked the same distance
12 meters
Therefore if You walk forward at 1.5 m / s for 8s
d = 1.5t [0,8] s
Your friend decides to walk faster and starts at 2.0 m / s for the first 4 s.
d = 2t [0,4] s
Then she slows down and walks forward at 1.0 m / s for the next 4s
d = t + 4 [4,8] s
Who walked farther?
They both walked the same distance
12 meters
Answer:
ΔT = 302 °c
Explanation:
mass (m) = 4.6 g = 0.0046 kg
velocity (v) = 278 m/s
specific heat of lead (c) = 128 J/kg. °c
kinetic energy = 0.5 mx
kinetic energy = 0.5 x 0.0046 x
kinetic energy = 177.8 J
since all the kinetic energy is converted to thermal energy,
kinetic energy = thermal energy (E) = 177.8 J
thermal energy = m x c x ΔT
where ΔT is the temperature change
177.8 = 0.0046 x 128 x ΔT
ΔT = 177.8 / 0.59
ΔT = 302 °c
Answer:
<em>The shortest distance to an object that this radar can detect would be </em>
<em>111 m</em>
Explanation:
The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;
T = 1/f ..........1
but f= v/λ substituting f into equation 1 we have;
T = λ/v...............2
Where λ is the wavelength = 2.2 m
v is the velocity of light since the radar is an electromagnetic wave
= 3 x m/s
T = 2.2 m / 3 x m/s
T = 7.33 x s
<u>Calculating the time interval required by the pulse</u>
Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;
t = 100 x T
t = 100 x 7.33 x s
t = 7.33 x s
Therefor the time of the pulse is 7.33 x s
<u>Calculating for the shortest distance of the radar</u>
The shortest distance of the radar can be obtained using the equation below;
λ_s = (t/2) x v ............3
Substituting into equation 3 we have
λ_s = (7.33 x /2) x 3 x
m/s
λ_s = 111 m
Therefore the shortest distance to an object that this radar can detect would be 111 m