Answer:
Coefficient of friction = 0.836
Explanation:
If v be the speed after one quarter of the circular path
v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8
tangential acceleration = 5.8 m/s²
radial acceleration = v² /r = 5.8
total acceleration = √2 x 5.8
m x√2 x 5.8 = m x g xμ
μ = √2 x 5.8 / 9.8 = 0.836
The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000
.
First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.
In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.
The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

where K is the constant of Coulomb's law.
In this case, you know:
- K= 9×10⁹

- q= 20 uC=20×10⁻⁶ C
- r= 1 m
Replacing in the definition of electric field:

Solving:
<u><em>E=180000 </em></u>
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Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000
.
Learn more:
Answer: A MA = 0.048
Explanation: 35 divided by 735 is equal to 0.048
D, water vapor. Gaseous state would have more kinetic energy, they are moving faster. If you have to compare the same state, then higher temperature would have the higher kinetic energy. But if you have solid and liquid at the same temperature - then liquid would have more.