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3 years ago

Need help ASAP

Physics

1 answer:

zhannawk [14.2K]3 years ago

5 0

For number one, the answer is the first dash mark

And for number two, the answer is the 4th dash.

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A small rocket with mass 20.0 kg is moving in free fall toward the earth. Air resistance can be neglected. When the rocket is 80

Mekhanik [1.2K]

Answer:

= 308.5 N

Explanation:

acceleration of rocket for safe landing

$v_{y} ^{2} = v_{0} ^{2} +2ay$

$a = \frac{v_{y}^{2} - v_{0}^{2} }{2y}$

$v_{0}$ = initial velocity

$v_{y}$ =final Velocity

m = mass of rocket

$\frac{0^{2} - 30^{2} }{2\times80}$

-5.625 $m/s^{2}$

Upward force

F - mg = ma

F = ma+ mg

F = m(a+g)

m= mass

a = 5.625 $m/s^{2}$

g = 9.8 $m/s^{2}$

= 20(5.625 $m/s^{2}$ + 9.8 $m/s^{2}$ )

= 308.5 N

7 0

3 years ago

The correctly balanced equation for H 2O 2 → H 2O + O 2 is

antoniya [11.8K]

2H2O + O2 -- 2H2O + O2 .

3 0

3 years ago

Match each term with the appropriate definition.

Ratling [72]

Answer:

mass- the amount of matter in an object

balance- tool used to measure mass

scale- a tool used to measure weight

weight- the downward pull on an object due to gravity

8 0

3 years ago

The total amount of kinetic energy and potential energy within a system is called

Alekssandra [29.7K]

The total amount of kinetic energy and potential energy within a system is called "Mechanical Energy"

In short, Your Answer would be Option C

Hope this helps!

6 0

3 years ago

Consider the specific example of a positive charge q moving in the +x direction with the local magnetic field in the +y directio

Leto [7]

Answer:

Therefore the direction is in the positive direction of the z axes.

Explanation:

Let's recall that the magnetic force is given by:

$F_{B}=q(\vec{v} \times \vec{B})$

The unit vector of V is $\hat{i}$ and the unit vector of B is $\hat{j}$

So, the direction of the force will be defined as the cross product of i and j, and using the right hand rule:

$\hat{i} \times \hat{j} = \hat{z}$

Therefore the direction of the magnetic force is in the positive direction of the z axes.

I hope it helps you!

4 0

4 years ago

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