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FinnZ [79.3K]
3 years ago
10

Solve |x + 3| – 1 = (x + 2)2 by graphing.

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

x= -2, -1

Step-by-step explanation: The solution is the x-value of the point of intersection

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What three numbers are the Pythagorean triple generated by using 4 for x and 1 for y. Remember to use the formulas:
sertanlavr [38]

Answer:

8, 15, and 17

Step-by-step explanation:

a=4^2 - 1^2 = 15 \\ \\ b=2(4)(1)=8 \\ \\ c=4^2 + 1^2 = 17

7 0
2 years ago
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7 0
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What is the product of the binomials below?
Otrada [13]

Answer:

The correct answer is 8x^2+28x+20.

Step-by-step explanation:

(2x+5)(4x+4)

Multiply the first bracket with each element of second bracket:

=4x(2x+5)+4(2x+5)

=8x^2+20x+8x+20

Now solve the like terms:

=8x^2+28x+20

Thus the correct answer is 8x^2+28x+20....

4 0
4 years ago
Pls help ill give brainliest
Ymorist [56]

Answer:

\boxed {\boxed {\sf (5g^2+2)(2g-5)}}

Step-by-step explanation:

We are given the expression:

10g^3-25g^2+4g-10

There are no common factors between the four numbers, however the first two have a common factor and the last two do too. Therefore, we can factor by grouping.

Group the first two terms and the last two.

(10g^3-25g^2)+(4g-10)

Find the greatest common factor (GCF) of the first group. It is 5g². Factor it out of the first group. You can do this by dividing both terms by the GCF.

  • 10g³/5g²= 2g
  • -25g²/5g² = -5

5g^2 (2g-5) + (4g-10)

Repeat with the second group. The GCF is 2.

  • 4g/2 = 2g
  • -10/2= -5

5g^2 (2g-5) + 2(2g-5)

There is another GCF: 2g-5. We can factor this out of both terms.

  • 5g²(2g-5)/2g-5= 5g²
  • 2(2g-5)/ 2g-5=2

(5g^2+2)(2g-5)

This cannot be factored further, so it is the answer.

4 0
3 years ago
Graph the following equation Y=3/4x-2
irina [24]
Your first point is your y-intercept, which is -2. That means you plot a point at (0,-2).

From that point rise 3 and run (to the right) 4. Plot your second point there.

Connect the two points.
4 0
3 years ago
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