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sleet_krkn [62]
3 years ago
5

Pleas e help me 100 points and brainliest

Mathematics
2 answers:
Vsevolod [243]3 years ago
4 0

Answer:

<h2>see the answers</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • factoring
  • lCD
  • PEMDAS
<h3>tips and formulas:</h3>
  • L.C.D=lowest common denominator
<h3>let's solve:</h3>

1)  \sf\frac{7}{m - 6} \:  ,  \frac{1}{m}  \\

denominators are m-6,m

therefore

the lowest common denominator is

<h2>(m-6)(m) </h2>

\sf\frac{1}{n - 1}  \: , \frac{1}{ {n}^{2} - 2n + 1 }

denominators n-1,n²-2n+1

step-1

factor n²-2n+1 to find the lowest common denominator

  • use (a-b)²=a²-2ab+b to factor n²-2n+1

therefore

  1. (n)²-2.n.1+(1)²
  2. (n-1)²

therefore

the L.C.D of the second expression is

<h3>(n-1)² </h3><h3>alternative form</h3><h3>(n-1)(n-1)</h3>

3)   \tt\frac{k}{ {h }^{2}  - 5h + 6}  \: , \frac{3}{h -3 }

step-1

factor out h²-5h+6 to find L.C.D

  1. rewrite -5h as -2h-3h: h²-2h-3h+6
  2. factor out h: h(h-2)-3h+6
  3. factor out -3: h(h-2)-3(h-2)
  4. group: (h-3)(h-2)

therefore

the L.C.D of the third expression is

<h2>(h-3)(h-2)</h2>
Roman55 [17]3 years ago
3 0

Answer:

this is your answer. I think it is right.

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