Answer:
y*(x+2)=k
so y= k/(x+2)
Step-by-step explanation:
Fourths, then b. Sorry if late.
Answer: 8x³ + 12x² - 16x - 16
<u>Step-by-step explanation:</u>
(4x² - 2x - 4)(2x + 4)
= (2x + 4)(4x² - 2x - 4)
= 2x(4x² - 2x - 4) + 4(4x² - 2x - 4)
= 8x³ - 4x² - 8x + 16x² - 8x - 16
= 8x³ + (-4x² + 16x²) + (-8x - 8x) - 16
= 8x³ + 12x² - 16x - 16
The third one is correcte
I don't know what the relation in your problem is, but I'll just explain this using my own example.
Let's use the following relation as the example (pretend it's a table of values):
x | y
0 | 1
2 | 4
4 | 7
6 | 10
To write the relation as ordered pairs, you need the x and y values from the table. An ordered pair is written like this: (x,y).
Based off of this explanation, the ordered pairs from this example would be:
(0,1) (2,4) (4,7) (6,10)
