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astraxan [27]
3 years ago
12

Need help on #1 thank youu!

Chemistry
2 answers:
olganol [36]3 years ago
7 0

Answer:

Oil---> Wood---> Water

Explanation:

Denser things always go on bottom. Since oil is on top is the least dense among those, and then comes wood and then finally water.

Juliette [100K]3 years ago
4 0
Oil , water , wood im pretty sure
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For the following reaction, 25.2 grams of sulfur dioxide are allowed to react with 5.36 grams of oxygen gas. sulfur dioxide (g)
Marizza181 [45]

Answer:

Maximum amount of sulfur trioxide that can be formed = 26.822 g

Explanation:

The balanced chemical equation for the reaction

2SO₂ + O₂ -----> 2SO₃

25.2 grams of sulfur dioxide are allowed to react with 5.36 grams of oxygen gas. What is the maximum amount of sulfur trioxide that can be formed?

It is the limiting reagent (the reactant in the stoichiometric lesser amount) that determines how much product is formed or how much of the other reactant is formed.

So, we convert the masses of reactants present into number of moles to get a clearer picture.

(Number of moles) = (mass)/(molar mass)

For sulfur dioxide,

Mass present = 25.2 g

Molar mass = 64.066 g/mol

(Number of moles present) = (25.2/64.066)

(Number of moles present) = 0.39 moles

For Oxygen gas,

Mass present = 5.36 g

Molar mass = 32.0 g/mol

(Number of moles present) = (5.36/32)

(Number of moles present) = 0.1675 moles

But from the stoichiometric balance,

2SO₂ + O₂ -----> 2SO₃

2 moles of Sulfur dioxide reacts with 1 mole of Oxygen gas

If Sulfur dioxide was the limiting reagent,

0.39 moles would react with (0.39×1/2) moles of Oxygen gas; 0.195 moles of Oxygen gas.

This is more than the total amount of Oxygen gas present at the start of the reaction, hence, Sulfur dioxide cannot be the limiting reagent.

Oxygen gas as limiting reagent,

1 mole of Oxygen gas reacts with 2 moles of Sulfur dioxide,

0.1675 moles of Oxygen gas would react with (0.1675×2/1) of Sulfur dioxide; 0.335 moles of Sulfur dioxide.

This indicates that oxygen is truly the limiting reagent and Sulfur dioxide is the reagent that is present in excess.

So, now, we calculate the amount of Sulfur trioxide that can be obtained from this reaction setup (assuming a 100% conversion and the maximum amount of Sulfur dioxide formed)

2SO₂ + O₂ -----> 2SO₃

1 mole of Oxygen gas gives 2 moles of Sulfur trioxide,

0.1675 moles of Oxygen gas will give (0.1675×2/1) moles of Sulfur trioxide; 0.335 moles of Sulfur trioxide.

We then convert this to mass.

(Mass) = (number of moles) × (molar mass)

Molar mass of SO₃ = 80.066 g/mol

(Mass of SO₃ produced) = 0.335 × 80.066

(Mass of SO₃ produced) = 26.822 g.

Maximum amount of sulfur trioxide that can be formed = 26.822 g

Hope this helps!!

5 0
3 years ago
Read 2 more answers
How could you ensure that all the spectroscopes used the same calibration line and equation? What would you need to be sure was
NISA [10]
People had asked this many times and that is why they came up with methods and standards that will answer these type of questions. You can look it up in the NIST or the  National Institute for Standards and Technology.
8 0
3 years ago
Answer seventeen please
kondor19780726 [428]
A. Ammonium = polyatomic ion
B. Oxygen = compound
C. Silver = element
D. Nitrate = polyatomic ion
E. Helium = element
F. Water = polyatomic ion
G. Nitrogen = element
H. Carbon dioxide = compound
3 0
3 years ago
1. write the formula for the following ionic compound: Calcium Carbonate
Salsk061 [2.6K]

Answer:

CaCO3

Explanation:

The molecule is formed by the calcium cation Ca+2 and the carbonate anion CO3−2.

3 0
2 years ago
What does it mean for a strong base to be in equilibrium?
prisoha [69]

The position of equilibrium lies far to the right, with products being favoured. Hence, option A is correct.

<h3>What is equilibrium?</h3>

Chemical equilibrium is a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.

A very high value of K indicates that at equilibrium most of the reactants are converted into products.

The equilibrium constant K is the ratio of the concentrations of products to the concentrations of reactants raised to appropriate stoichiometric coefficients.

When the value of the equilibrium constant is very high, the concentration of products is much higher than the concentration of reactants.

This means that most of the reactants are converted into products and the position of equilibrium lies far to the right, with products being favoured.

Hence, option A is correct.

Learn more about the equilibrium here:

brainly.com/question/23641529

#SPJ1

8 0
2 years ago
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