Note:xy means x times y and x(y) means the same thing
so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0
squareroot(y-1)+3=y
isolate the squareroot
subtrac 3 from boht sides
squareroot(y-1)=y-3
square both sides (since they are equal, you should be able to square both sides and still make it true)
(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5
0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0
therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work
let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true
y=5
Answer:
-.6
Step-by-step explanation:
-2.1 - x = -1 1/2
Change the fraction to a decimal
-2.1 -x = - 1.5
Add 2.1 to each side
-2.1 -x+2.1 = -1.5 +2.1
-x = .6
Multiply each side by -1
x = -.6
Answer:
C
Step-by-step explanation:
Tell me if you need or want an explanation
Answer:
-3
Step-by-step explanation:
The statement is,
→ Sum of 9 and -16 increased by 4
The equation will be,
→ {9 +(-16)} + 4
→ (9 - 16) + 4
→ -7 + 4
→ [ -3 ]
Hence, the solution is -3.
Answer:
a₈ = - 1 / 128
Step-by-step explanation:
Given:
First four terms of the sequence
a₁= 1, a₂= - 1/2, a₃= 1/4 and a₄= -1/8
First we recognize that this is a geometric series (sequence) and we must calculate quotient q.
q = a₂/a₁ = a₃/a₂ = (-1/2)/1 = (1/4)/(-1/2) = - 1/2
q = - 1/2
Formula for calculating n-th term is:
aₙ = a₁ · qⁿ⁻¹
According to this:
a₈ = 1 (-1/2)⁷ = - 1/ 128
God with you!!!
