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Allisa [31]
3 years ago
9

5c+4 = 2 (c – 5) What is the solution?

Mathematics
2 answers:
dybincka [34]3 years ago
8 0

Answer:

0

Step-by-step explanation:

if I'm correct it's 0 because when you do all of the math that's what it came out to

lukranit [14]3 years ago
3 0
C=-14/3
if that helps :)
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Solve n + 5(n - 1) = 7
Nina [5.8K]

Answer:

N = 2

Step-by-step explanation:

n + 5(n-1) = 7

n + 5n - 5 = 7

6n - 5 = 7

6n = 12

n = 2

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7 0
3 years ago
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F(x)=4(x+2)(x+2)-6 in standard form
ollegr [7]

Answer:

4x^2 + 4x -2

Step-by-step explanation:

Use FOIL to solve (x+2) (x+2)

4(x^2 + 4x +4) - 6

4x^2 + 4x -2

8 0
3 years ago
Help me please !!!!! ASAP !
irga5000 [103]

Answer:

x = 6 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

6^2+ x^2 = 12^2

36 + x^2 = 144

Subtract 36 from each side

x^2 = 144-36

x^2 =108

Take the square root of each side

sqrt(x^2) = sqrt(108)

x = sqrt(36*3)

x = 6 sqrt(3)

8 0
2 years ago
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Ivenika [448]

Answer:

3.5 min

Step-by-step explanation:

5 0
3 years ago
Please answer this question now
Rashid [163]

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

4 0
3 years ago
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